Utility Functions for Cryptography#
Miscellaneous utility functions for cryptographic purposes.
AUTHORS:
Minh Van Nguyen (2009-12): initial version with the following functions:
ascii_integer
,ascii_to_bin
,bin_to_ascii
,has_blum_prime
,is_blum_prime
,least_significant_bits
,random_blum_prime
.
- sage.crypto.util.ascii_integer(B)#
Return the ASCII integer corresponding to the binary string
B
.INPUT:
B
– a non-empty binary string or a non-empty list of bits. The number of bits inB
must be 8.
OUTPUT:
The ASCII integer corresponding to the 8-bit block
B
.
EXAMPLES:
The ASCII integers of some binary strings:
sage: from sage.crypto.util import ascii_integer sage: bin = BinaryStrings() sage: B = bin.encoding("A"); B 01000001 sage: ascii_integer(B) 65 sage: B = bin.encoding("C"); list(B) [0, 1, 0, 0, 0, 0, 1, 1] sage: ascii_integer(list(B)) 67 sage: ascii_integer("01000100") 68 sage: ascii_integer([0, 1, 0, 0, 0, 1, 0, 1]) 69
- sage.crypto.util.ascii_to_bin(A)#
Return the binary representation of the ASCII string
A
.INPUT:
A
– a string or list of ASCII characters.
OUTPUT:
The binary representation of
A
.
ALGORITHM:
Let \(A = a_0 a_1 \cdots a_{n-1}\) be an ASCII string, where each \(a_i\) is an ASCII character. Let \(c_i\) be the ASCII integer corresponding to \(a_i\) and let \(b_i\) be the binary representation of \(c_i\). The binary representation \(B\) of \(A\) is \(B = b_0 b_1 \cdots b_{n-1}\).
EXAMPLES:
The binary representation of some ASCII strings:
sage: from sage.crypto.util import ascii_to_bin sage: ascii_to_bin("A") 01000001 sage: ascii_to_bin("Abc123") 010000010110001001100011001100010011001000110011
The empty string is different from the string with one space character. For the empty string and the empty list, this function returns the same result:
sage: from sage.crypto.util import ascii_to_bin sage: ascii_to_bin("") sage: ascii_to_bin(" ") 00100000 sage: ascii_to_bin([])
This function also accepts a list of ASCII characters. You can also pass in a list of strings:
sage: from sage.crypto.util import ascii_to_bin sage: ascii_to_bin(["A", "b", "c", "1", "2", "3"]) 010000010110001001100011001100010011001000110011 sage: ascii_to_bin(["A", "bc", "1", "23"]) 010000010110001001100011001100010011001000110011
- sage.crypto.util.bin_to_ascii(B)#
Return the ASCII representation of the binary string
B
.INPUT:
B
– a non-empty binary string or a non-empty list of bits. The number of bits inB
must be a multiple of 8.
OUTPUT:
The ASCII string corresponding to
B
.
ALGORITHM:
Consider a block of bits \(B = b_0 b_1 \cdots b_{n-1}\) where each sub-block \(b_i\) is a binary string of length 8. Then the total number of bits is a multiple of 8 and is given by \(8n\). Let \(c_i\) be the integer representation of \(b_i\). We can consider \(c_i\) as the integer representation of an ASCII character. Then the ASCII representation \(A\) of \(B\) is \(A = a_0 a_1 \cdots a_{n-1}\).
EXAMPLES:
Convert some ASCII strings to their binary representations and recover the ASCII strings from the binary representations:
sage: from sage.crypto.util import ascii_to_bin sage: from sage.crypto.util import bin_to_ascii sage: A = "Abc" sage: B = ascii_to_bin(A); B 010000010110001001100011 sage: bin_to_ascii(B) 'Abc' sage: bin_to_ascii(B) == A True
sage: A = "123 \" #" sage: B = ascii_to_bin(A); B 00110001001100100011001100100000001000100010000000100011 sage: bin_to_ascii(B) '123 " #' sage: bin_to_ascii(B) == A True
This function also accepts strings and lists of bits:
sage: from sage.crypto.util import bin_to_ascii sage: bin_to_ascii("010000010110001001100011") 'Abc' sage: bin_to_ascii([0, 1, 0, 0, 0, 0, 0, 1]) 'A'
- sage.crypto.util.has_blum_prime(lbound, ubound)#
Determine whether or not there is a Blum prime within the specified closed interval.
INPUT:
lbound
– positive integer; the lower bound on how small a Blum prime can be. The lower bound must be distinct from the upper bound.ubound
– positive integer; the upper bound on how large a Blum prime can be. The lower bound must be distinct from the upper bound.
OUTPUT:
True
if there is a Blum primep
such thatlbound <= p <= ubound
.False
otherwise.
ALGORITHM:
Let \(L\) and \(U\) be distinct positive integers. Let \(P\) be the set of all odd primes \(p\) such that \(L \leq p \leq U\). Our main focus is on Blum primes, i.e. odd primes that are congruent to 3 modulo 4, so we assume that the lower bound \(L > 2\). The closed interval \([L, U]\) has a Blum prime if and only if the set \(P\) has a Blum prime.
EXAMPLES:
Testing for the presence of Blum primes within some closed intervals. The interval \([4, 100]\) has a Blum prime, the smallest such prime being 7. The interval \([24, 28]\) has no primes, hence no Blum primes.
sage: from sage.crypto.util import has_blum_prime sage: from sage.crypto.util import is_blum_prime sage: has_blum_prime(4, 100) # needs sage.libs.pari True sage: for n in range(4, 100): ....: if is_blum_prime(n): ....: print(n) ....: break 7 sage: has_blum_prime(24, 28) # needs sage.libs.pari False
- sage.crypto.util.is_blum_prime(n)#
Determine whether or not
n
is a Blum prime.INPUT:
n
a positive prime.
OUTPUT:
True
ifn
is a Blum prime;False
otherwise.
Let \(n\) be a positive prime. Then \(n\) is a Blum prime if \(n\) is congruent to 3 modulo 4, i.e. \(n \equiv 3 \pmod{4}\).
EXAMPLES:
Testing some integers to see if they are Blum primes:
sage: from sage.crypto.util import is_blum_prime sage: from sage.crypto.util import random_blum_prime sage: is_blum_prime(101) False sage: is_blum_prime(7) True sage: p = random_blum_prime(10**3, 10**5) # needs sage.libs.pari sage: is_blum_prime(p) # needs sage.libs.pari True
- sage.crypto.util.least_significant_bits(n, k)#
Return the
k
least significant bits ofn
.INPUT:
n
– an integer.k
– a positive integer.
OUTPUT:
The
k
least significant bits of the integern
. Ifk=1
, then return the parity bit of the integern
. Let \(b\) be the binary representation ofn
, where \(m\) is the length of the binary string \(b\). If \(k \geq m\), then return the binary representation ofn
.
EXAMPLES:
Obtain the parity bits of some integers:
sage: from sage.crypto.util import least_significant_bits sage: least_significant_bits(0, 1) [0] sage: least_significant_bits(2, 1) [0] sage: least_significant_bits(3, 1) [1] sage: least_significant_bits(-2, 1) [0] sage: least_significant_bits(-3, 1) [1]
Obtain the 4 least significant bits of some integers:
sage: least_significant_bits(101, 4) [0, 1, 0, 1] sage: least_significant_bits(-101, 4) [0, 1, 0, 1] sage: least_significant_bits(124, 4) [1, 1, 0, 0] sage: least_significant_bits(-124, 4) [1, 1, 0, 0]
The binary representation of 123:
sage: n = 123; b = n.binary(); b '1111011' sage: least_significant_bits(n, len(b)) [1, 1, 1, 1, 0, 1, 1]
- sage.crypto.util.random_blum_prime(lbound, ubound, ntries=100)#
A random Blum prime within the specified bounds.
Let \(p\) be a positive prime. Then \(p\) is a Blum prime if \(p\) is congruent to 3 modulo 4, i.e. \(p \equiv 3 \pmod{4}\).
INPUT:
lbound
– positive integer; the lower bound on how small a random Blum prime \(p\) can be. So we have0 < lbound <= p <= ubound
. The lower bound must be distinct from the upper bound.ubound
– positive integer; the upper bound on how large a random Blum prime \(p\) can be. So we have0 < lbound <= p <= ubound
. The lower bound must be distinct from the upper bound.ntries
– (default:100
) the number of attempts to generate a random Blum prime. Ifntries
is a positive integer, then perform that many attempts at generating a random Blum prime. This might or might not result in a Blum prime.
OUTPUT:
A random Blum prime within the specified lower and upper bounds.
Note
Beware that there might not be any primes between the lower and upper bounds. So make sure that these two bounds are “sufficiently” far apart from each other for there to be primes congruent to 3 modulo 4. In particular, there should be at least two distinct Blum primes within the specified bounds.
EXAMPLES:
Choose a random prime and check that it is a Blum prime:
sage: from sage.crypto.util import random_blum_prime sage: p = random_blum_prime(10**4, 10**5) # needs sage.libs.pari sage: is_prime(p) # needs sage.libs.pari True sage: mod(p, 4) == 3 # needs sage.libs.pari True