# Discrete Gaussian Samplers over Lattices¶

This file implements oracles which return samples from a lattice following a discrete Gaussian distribution. That is, if $$σ$$ is big enough relative to the provided basis, then vectors are returned with a probability proportional to $$\exp(-|x-c|_2^2/(2σ^2))$$. More precisely lattice vectors in $$x ∈ Λ$$ are returned with probability:

$$\exp(-|x-c|_2^2/(2σ²))/(∑_{x ∈ Λ} \exp(-|x|_2^2/(2σ²)))$$

AUTHORS:

• Martin Albrecht (2014-06-28): initial version

EXAMPLES:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: D = DiscreteGaussianDistributionLatticeSampler(ZZ^10, 3.0)
sage: D(), D(), D()
((3, 0, -5, 0, -1, -3, 3, 3, -7, 2), (4, 0, 1, -2, -4, -4, 4, 0, 1, -4), (-3, 0, 4, 5, 0, 1, 3, 2, 0, -1))

class sage.stats.distributions.discrete_gaussian_lattice.DiscreteGaussianDistributionLatticeSampler(B, sigma=1, c=None, precision=None)

GPV sampler for Discrete Gaussians over Lattices.

EXAMPLES:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: D = DiscreteGaussianDistributionLatticeSampler(ZZ^10, 3.0); D
Discrete Gaussian sampler with σ = 3.000000, c=(0, 0, 0, 0, 0, 0, 0, 0, 0, 0) over lattice with basis

[1 0 0 0 0 0 0 0 0 0]
[0 1 0 0 0 0 0 0 0 0]
[0 0 1 0 0 0 0 0 0 0]
[0 0 0 1 0 0 0 0 0 0]
[0 0 0 0 1 0 0 0 0 0]
[0 0 0 0 0 1 0 0 0 0]
[0 0 0 0 0 0 1 0 0 0]
[0 0 0 0 0 0 0 1 0 0]
[0 0 0 0 0 0 0 0 1 0]
[0 0 0 0 0 0 0 0 0 1]


We plot a histogram:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: import warnings
sage: warnings.simplefilter('ignore', UserWarning)
sage: D = DiscreteGaussianDistributionLatticeSampler(identity_matrix(2), 3.0)
sage: S = [D() for _ in range(2^12)]
sage: l = [vector(v.list() + [S.count(v)]) for v in set(S)]
sage: list_plot3d(l, point_list=True, interpolation='nn')
Graphics3d Object


REFERENCES:

__init__(B, sigma=1, c=None, precision=None)

Construct a discrete Gaussian sampler over the lattice $$Λ(B)$$ with parameter sigma and center $$c$$.

INPUT:

• B – a basis for the lattice, one of the following:
• an integer matrix,
• an object with a matrix() method, e.g. ZZ^n, or
• an object where matrix(B) succeeds, e.g. a list of vectors.
• sigma – Gaussian parameter $$σ>0$$.
• c – center $$c$$, any vector in $$\ZZ^n$$ is supported, but $$c ∈ Λ(B)$$ is faster.
• precision – bit precision $$≥ 53$$.

EXAMPLES:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: n = 2; sigma = 3.0; m = 5000
sage: D = DiscreteGaussianDistributionLatticeSampler(ZZ^n, sigma)
sage: f = D.f
sage: c = D._normalisation_factor_zz(); c
56.2162803067524

sage: l = [D() for _ in range(m)]
sage: v = vector(ZZ, n, (-3,-3))
sage: l.count(v), ZZ(round(m*f(v)/c))
(39, 33)

sage: target = vector(ZZ, n, (0,0))
sage: l.count(target), ZZ(round(m*f(target)/c))
(116, 89)

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: qf = QuadraticForm(matrix(3, [2, 1, 1,  1, 2, 1,  1, 1, 2]))
sage: D = DiscreteGaussianDistributionLatticeSampler(qf, 3.0); D
Discrete Gaussian sampler with σ = 3.000000, c=(0, 0, 0) over lattice with basis

[2 1 1]
[1 2 1]
[1 1 2]
sage: D()
(0, 1, -1)

__call__()

Return a new sample.

EXAMPLES:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: D = DiscreteGaussianDistributionLatticeSampler(ZZ^3, 3.0, c=(1,0,0))
sage: L = [D() for _ in range(2^12)]
sage: abs(mean(L).n() - D.c)
0.08303258...

sage: D = DiscreteGaussianDistributionLatticeSampler(ZZ^3, 3.0, c=(1/2,0,0))
sage: L = [D() for _ in range(2^12)] # long time
sage: mean(L).n() - D.c # long time
(0.0607910156250000, -0.128417968750000, 0.0239257812500000)

c

Center $$c$$.

Samples from this sampler will be centered at $$c$$.

EXAMPLES:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: D = DiscreteGaussianDistributionLatticeSampler(ZZ^3, 3.0, c=(1,0,0)); D
Discrete Gaussian sampler with σ = 3.000000, c=(1, 0, 0) over lattice with basis

[1 0 0]
[0 1 0]
[0 0 1]

sage: D.c
(1, 0, 0)

static compute_precision(precision, sigma)

Compute precision to use.

INPUT:

• precision - an integer $$> 53$$ nor None.
• sigma - if precision is None then the precision of sigma is used.

EXAMPLES:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: DiscreteGaussianDistributionLatticeSampler.compute_precision(100, RR(3))
100
sage: DiscreteGaussianDistributionLatticeSampler.compute_precision(100, RealField(200)(3))
100
sage: DiscreteGaussianDistributionLatticeSampler.compute_precision(100, 3)
100
sage: DiscreteGaussianDistributionLatticeSampler.compute_precision(None, RR(3))
53
sage: DiscreteGaussianDistributionLatticeSampler.compute_precision(None, RealField(200)(3))
200
sage: DiscreteGaussianDistributionLatticeSampler.compute_precision(None, 3)
53

sigma

Gaussian parameter $$σ$$.

Samples from this sampler will have expected norm $$\sqrt{n}σ$$ where $$n$$ is the dimension of the lattice.

EXAMPLES:

sage: from sage.stats.distributions.discrete_gaussian_lattice import DiscreteGaussianDistributionLatticeSampler
sage: D = DiscreteGaussianDistributionLatticeSampler(ZZ^3, 3.0, c=(1,0,0))
sage: D.sigma
3.00000000000000