Double Description for Arbitrary Polyhedra¶
This module is part of the python backend for polyhedra. It uses the
double description method for cones
double_description
to find minimal
H/V-representations of polyhedra. The latter works with cones
only. This is sufficient to treat general polyhedra by the following
construction: Any polyhedron can be embedded in one dimension higher
in the hyperplane \((1, *, \dots, *)\). The cone over the embedded
polyhedron will be called the homogenized cone in the
following. Conversely, intersecting the homogenized cone with the
hyperplane \(x_0=1\) gives you back the original polyhedron.
While slower than specialized C/C++ implementations, the implementation is general and works with any field in Sage that allows you to define polyhedra.
Note
If you just want polyhedra over arbitrary fields then you should
just use the
Polyhedron()
constructor.
EXAMPLES:
sage: from sage.geometry.polyhedron.double_description_inhomogeneous \
....: import Hrep2Vrep, Vrep2Hrep
sage: Hrep2Vrep(QQ, 2, [(1,2,3), (2,4,3)], [])
[-1/2|-1/2 1/2|]
[ 0| 2/3 -1/3|]
>>> from sage.all import *
>>> from sage.geometry.polyhedron.double_description_inhomogeneous import Hrep2Vrep, Vrep2Hrep
>>> Hrep2Vrep(QQ, Integer(2), [(Integer(1),Integer(2),Integer(3)), (Integer(2),Integer(4),Integer(3))], [])
[-1/2|-1/2 1/2|]
[ 0| 2/3 -1/3|]
Note that the columns of the printed matrix are the vertices, rays, and lines of the minimal V-representation. Dually, the rows of the following are the inequalities and equations:
sage: Vrep2Hrep(QQ, 2, [(-1/2,0)], [(-1/2,2/3), (1/2,-1/3)], [])
[1 2 3]
[2 4 3]
[-----]
>>> from sage.all import *
>>> Vrep2Hrep(QQ, Integer(2), [(-Integer(1)/Integer(2),Integer(0))], [(-Integer(1)/Integer(2),Integer(2)/Integer(3)), (Integer(1)/Integer(2),-Integer(1)/Integer(3))], [])
[1 2 3]
[2 4 3]
[-----]
- class sage.geometry.polyhedron.double_description_inhomogeneous.Hrep2Vrep(base_ring, dim, inequalities, equations)[source]¶
Bases:
PivotedInequalities
Convert H-representation to a minimal V-representation.
INPUT:
base_ring
– a fielddim
– integer; the ambient space dimensioninequalities
– list of inequalities; each inequality is given as constant term,dim
coefficientsequations
– list of equations; same notation as for inequalities
EXAMPLES:
sage: from sage.geometry.polyhedron.double_description_inhomogeneous import Hrep2Vrep sage: Hrep2Vrep(QQ, 2, [(1,2,3), (2,4,3)], []) [-1/2|-1/2 1/2|] [ 0| 2/3 -1/3|] sage: Hrep2Vrep(QQ, 2, [(1,2,3), (2,-2,-3)], []) [ 1 -1/2|| 1] [ 0 0||-2/3] sage: Hrep2Vrep(QQ, 2, [(1,2,3), (2,2,3)], []) [-1/2| 1/2| 1] [ 0| 0|-2/3] sage: Hrep2Vrep(QQ, 2, [(8,7,-2), (1,-4,3), (4,-3,-1)], []) [ 1 0 -2||] [ 1 4 -3||] sage: Hrep2Vrep(QQ, 2, [(1,2,3), (2,4,3), (5,-1,-2)], []) [-19/5 -1/2| 2/33 1/11|] [ 22/5 0|-1/33 -2/33|] sage: Hrep2Vrep(QQ, 2, [(0,2,3), (0,4,3), (0,-1,-2)], []) [ 0| 1/2 1/3|] [ 0|-1/3 -1/6|] sage: Hrep2Vrep(QQ, 2, [], [(1,2,3), (7,8,9)]) [-2||] [ 1||] sage: Hrep2Vrep(QQ, 2, [(1,0,0)], []) # universe [0||1 0] [0||0 1] sage: Hrep2Vrep(QQ, 2, [(-1,0,0)], []) # empty [] sage: Hrep2Vrep(QQ, 2, [], []) # universe [0||1 0] [0||0 1]
>>> from sage.all import * >>> from sage.geometry.polyhedron.double_description_inhomogeneous import Hrep2Vrep >>> Hrep2Vrep(QQ, Integer(2), [(Integer(1),Integer(2),Integer(3)), (Integer(2),Integer(4),Integer(3))], []) [-1/2|-1/2 1/2|] [ 0| 2/3 -1/3|] >>> Hrep2Vrep(QQ, Integer(2), [(Integer(1),Integer(2),Integer(3)), (Integer(2),-Integer(2),-Integer(3))], []) [ 1 -1/2|| 1] [ 0 0||-2/3] >>> Hrep2Vrep(QQ, Integer(2), [(Integer(1),Integer(2),Integer(3)), (Integer(2),Integer(2),Integer(3))], []) [-1/2| 1/2| 1] [ 0| 0|-2/3] >>> Hrep2Vrep(QQ, Integer(2), [(Integer(8),Integer(7),-Integer(2)), (Integer(1),-Integer(4),Integer(3)), (Integer(4),-Integer(3),-Integer(1))], []) [ 1 0 -2||] [ 1 4 -3||] >>> Hrep2Vrep(QQ, Integer(2), [(Integer(1),Integer(2),Integer(3)), (Integer(2),Integer(4),Integer(3)), (Integer(5),-Integer(1),-Integer(2))], []) [-19/5 -1/2| 2/33 1/11|] [ 22/5 0|-1/33 -2/33|] >>> Hrep2Vrep(QQ, Integer(2), [(Integer(0),Integer(2),Integer(3)), (Integer(0),Integer(4),Integer(3)), (Integer(0),-Integer(1),-Integer(2))], []) [ 0| 1/2 1/3|] [ 0|-1/3 -1/6|] >>> Hrep2Vrep(QQ, Integer(2), [], [(Integer(1),Integer(2),Integer(3)), (Integer(7),Integer(8),Integer(9))]) [-2||] [ 1||] >>> Hrep2Vrep(QQ, Integer(2), [(Integer(1),Integer(0),Integer(0))], []) # universe [0||1 0] [0||0 1] >>> Hrep2Vrep(QQ, Integer(2), [(-Integer(1),Integer(0),Integer(0))], []) # empty [] >>> Hrep2Vrep(QQ, Integer(2), [], []) # universe [0||1 0] [0||0 1]
- verify(inequalities, equations)[source]¶
Compare result to PPL if the base ring is QQ.
This method is for debugging purposes and compares the computation with another backend if available.
INPUT:
inequalities
,equations
– seeHrep2Vrep
EXAMPLES:
sage: from sage.geometry.polyhedron.double_description_inhomogeneous import Hrep2Vrep sage: H = Hrep2Vrep(QQ, 1, [(1,2)], []) sage: H.verify([(1,2)], [])
>>> from sage.all import * >>> from sage.geometry.polyhedron.double_description_inhomogeneous import Hrep2Vrep >>> H = Hrep2Vrep(QQ, Integer(1), [(Integer(1),Integer(2))], []) >>> H.verify([(Integer(1),Integer(2))], [])
- class sage.geometry.polyhedron.double_description_inhomogeneous.PivotedInequalities(base_ring, dim)[source]¶
Bases:
SageObject
Base class for inequalities that may contain linear subspaces.
INPUT:
base_ring
– a fielddim
– integer; the ambient space dimension
EXAMPLES:
sage: from sage.geometry.polyhedron.double_description_inhomogeneous ....: import PivotedInequalities sage: piv = PivotedInequalities(QQ, 2) sage: piv._pivot_inequalities(matrix([(1,1,3), (5,5,7)])) [1 3] [5 7] sage: piv._pivots (0, 2) sage: piv._linear_subspace Free module of degree 3 and rank 1 over Integer Ring Echelon basis matrix: [ 1 -1 0]
>>> from sage.all import * >>> from sage.geometry.polyhedron.double_description_inhomogeneous Ellipsis.: import PivotedInequalities >>> piv = PivotedInequalities(QQ, Integer(2)) >>> piv._pivot_inequalities(matrix([(Integer(1),Integer(1),Integer(3)), (Integer(5),Integer(5),Integer(7))])) [1 3] [5 7] >>> piv._pivots (0, 2) >>> piv._linear_subspace Free module of degree 3 and rank 1 over Integer Ring Echelon basis matrix: [ 1 -1 0]
- class sage.geometry.polyhedron.double_description_inhomogeneous.Vrep2Hrep(base_ring, dim, vertices, rays, lines)[source]¶
Bases:
PivotedInequalities
Convert V-representation to a minimal H-representation.
INPUT:
base_ring
– a fielddim
– integer; the ambient space dimensionvertices
– list of vertices; each vertex is given as list ofdim
coordinatesrays
– list of rays; each ray is given as list ofdim
coordinates, not all zerolines
– list of line generators; each line is given as list ofdim
coordinates, not all zero
EXAMPLES:
sage: from sage.geometry.polyhedron.double_description_inhomogeneous import Vrep2Hrep sage: Vrep2Hrep(QQ, 2, [(-1/2,0)], [(-1/2,2/3), (1/2,-1/3)], []) [1 2 3] [2 4 3] [-----] sage: Vrep2Hrep(QQ, 2, [(1,0), (-1/2,0)], [], [(1,-2/3)]) [ 1/3 2/3 1] [ 2/3 -2/3 -1] [--------------] sage: Vrep2Hrep(QQ, 2, [(-1/2,0)], [(1/2,0)], [(1,-2/3)]) [1 2 3] [-----] sage: Vrep2Hrep(QQ, 2, [(1,1), (0,4), (-2,-3)], [], []) [ 8/13 7/13 -2/13] [ 1/13 -4/13 3/13] [ 4/13 -3/13 -1/13] [-----------------] sage: Vrep2Hrep(QQ, 2, [(-19/5,22/5), (-1/2,0)], [(2/33,-1/33), (1/11,-2/33)], []) [10/11 -2/11 -4/11] [ 66/5 132/5 99/5] [ 2/11 4/11 6/11] [-----------------] sage: Vrep2Hrep(QQ, 2, [(0,0)], [(1/2,-1/3), (1/3,-1/6)], []) [ 0 -6 -12] [ 0 12 18] [-----------] sage: Vrep2Hrep(QQ, 2, [(-1/2,0)], [], [(1,-2/3)]) [-----] [1 2 3] sage: Vrep2Hrep(QQ, 2, [(-1/2,0)], [], [(1,-2/3), (1,0)]) []
>>> from sage.all import * >>> from sage.geometry.polyhedron.double_description_inhomogeneous import Vrep2Hrep >>> Vrep2Hrep(QQ, Integer(2), [(-Integer(1)/Integer(2),Integer(0))], [(-Integer(1)/Integer(2),Integer(2)/Integer(3)), (Integer(1)/Integer(2),-Integer(1)/Integer(3))], []) [1 2 3] [2 4 3] [-----] >>> Vrep2Hrep(QQ, Integer(2), [(Integer(1),Integer(0)), (-Integer(1)/Integer(2),Integer(0))], [], [(Integer(1),-Integer(2)/Integer(3))]) [ 1/3 2/3 1] [ 2/3 -2/3 -1] [--------------] >>> Vrep2Hrep(QQ, Integer(2), [(-Integer(1)/Integer(2),Integer(0))], [(Integer(1)/Integer(2),Integer(0))], [(Integer(1),-Integer(2)/Integer(3))]) [1 2 3] [-----] >>> Vrep2Hrep(QQ, Integer(2), [(Integer(1),Integer(1)), (Integer(0),Integer(4)), (-Integer(2),-Integer(3))], [], []) [ 8/13 7/13 -2/13] [ 1/13 -4/13 3/13] [ 4/13 -3/13 -1/13] [-----------------] >>> Vrep2Hrep(QQ, Integer(2), [(-Integer(19)/Integer(5),Integer(22)/Integer(5)), (-Integer(1)/Integer(2),Integer(0))], [(Integer(2)/Integer(33),-Integer(1)/Integer(33)), (Integer(1)/Integer(11),-Integer(2)/Integer(33))], []) [10/11 -2/11 -4/11] [ 66/5 132/5 99/5] [ 2/11 4/11 6/11] [-----------------] >>> Vrep2Hrep(QQ, Integer(2), [(Integer(0),Integer(0))], [(Integer(1)/Integer(2),-Integer(1)/Integer(3)), (Integer(1)/Integer(3),-Integer(1)/Integer(6))], []) [ 0 -6 -12] [ 0 12 18] [-----------] >>> Vrep2Hrep(QQ, Integer(2), [(-Integer(1)/Integer(2),Integer(0))], [], [(Integer(1),-Integer(2)/Integer(3))]) [-----] [1 2 3] >>> Vrep2Hrep(QQ, Integer(2), [(-Integer(1)/Integer(2),Integer(0))], [], [(Integer(1),-Integer(2)/Integer(3)), (Integer(1),Integer(0))]) []
- verify(vertices, rays, lines)[source]¶
Compare result to PPL if the base ring is QQ.
This method is for debugging purposes and compares the computation with another backend if available.
INPUT:
vertices
,rays
,lines
– seeVrep2Hrep
EXAMPLES:
sage: from sage.geometry.polyhedron.double_description_inhomogeneous import Vrep2Hrep sage: vertices = [(-1/2,0)] sage: rays = [(-1/2,2/3), (1/2,-1/3)] sage: lines = [] sage: V2H = Vrep2Hrep(QQ, 2, vertices, rays, lines) sage: V2H.verify(vertices, rays, lines)
>>> from sage.all import * >>> from sage.geometry.polyhedron.double_description_inhomogeneous import Vrep2Hrep >>> vertices = [(-Integer(1)/Integer(2),Integer(0))] >>> rays = [(-Integer(1)/Integer(2),Integer(2)/Integer(3)), (Integer(1)/Integer(2),-Integer(1)/Integer(3))] >>> lines = [] >>> V2H = Vrep2Hrep(QQ, Integer(2), vertices, rays, lines) >>> V2H.verify(vertices, rays, lines)