\(k\)-regular sequences¶
An introduction and formal definition of \(k\)-regular sequences can be found, for example, on the Wikipedia article k-regular_sequence or in [AS2003].
sage: import logging
sage: logging.basicConfig()
>>> from sage.all import *
>>> import logging
>>> logging.basicConfig()
Examples¶
Binary sum of digits¶
The binary sum of digits \(S(n)\) of a nonnegative integer \(n\) satisfies \(S(2n) = S(n)\) and \(S(2n+1) = S(n) + 1\). We model this by the following:
sage: Seq2 = RegularSequenceRing(2, ZZ)
sage: S = Seq2((Matrix([[1, 0], [0, 1]]), Matrix([[1, 0], [1, 1]])),
....: left=vector([0, 1]), right=vector([1, 0]))
sage: S
2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ...
sage: all(S[n] == sum(n.digits(2)) for n in srange(10))
True
>>> from sage.all import *
>>> Seq2 = RegularSequenceRing(Integer(2), ZZ)
>>> S = Seq2((Matrix([[Integer(1), Integer(0)], [Integer(0), Integer(1)]]), Matrix([[Integer(1), Integer(0)], [Integer(1), Integer(1)]])),
... left=vector([Integer(0), Integer(1)]), right=vector([Integer(1), Integer(0)]))
>>> S
2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ...
>>> all(S[n] == sum(n.digits(Integer(2))) for n in srange(Integer(10)))
True
Number of odd entries in Pascal’s triangle¶
Let us consider the number of odd entries in the first \(n\) rows of Pascals’s triangle:
sage: @cached_function
....: def u(n):
....: if n <= 1:
....: return n
....: return 2 * u(n // 2) + u((n+1) // 2)
sage: tuple(u(n) for n in srange(10))
(0, 1, 3, 5, 9, 11, 15, 19, 27, 29)
>>> from sage.all import *
>>> @cached_function
... def u(n):
... if n <= Integer(1):
... return n
... return Integer(2) * u(n // Integer(2)) + u((n+Integer(1)) // Integer(2))
>>> tuple(u(n) for n in srange(Integer(10)))
(0, 1, 3, 5, 9, 11, 15, 19, 27, 29)
There is a \(2\)-regular sequence describing the numbers above as well:
sage: U = Seq2((Matrix([[3, 0], [2, 1]]), Matrix([[2, 1], [0, 3]])),
....: left=vector([1, 0]), right=vector([0, 1]))
sage: all(U[n] == u(n) for n in srange(30))
True
>>> from sage.all import *
>>> U = Seq2((Matrix([[Integer(3), Integer(0)], [Integer(2), Integer(1)]]), Matrix([[Integer(2), Integer(1)], [Integer(0), Integer(3)]])),
... left=vector([Integer(1), Integer(0)]), right=vector([Integer(0), Integer(1)]))
>>> all(U[n] == u(n) for n in srange(Integer(30)))
True
Various¶
See also
recognizable series
,
sage.rings.cfinite_sequence
,
sage.combinat.binary_recurrence_sequences
.
AUTHORS:
Daniel Krenn (2016, 2021)
Gabriel F. Lipnik (2021)
ACKNOWLEDGEMENT:
Daniel Krenn is supported by the Austrian Science Fund (FWF): P 24644-N26.
Gabriel F. Lipnik is supported by the Austrian Science Fund (FWF): W 1230.
Classes and Methods¶
- exception sage.combinat.regular_sequence.DegeneratedSequenceError[source]¶
Bases:
RuntimeError
Exception raised if a degenerated sequence (see
is_degenerated()
) is detected.EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: Seq2((Matrix([2]), Matrix([3])), vector([1]), vector([1])) Traceback (most recent call last): ... DegeneratedSequenceError: degenerated sequence: mu[0]*right != right. Using such a sequence might lead to wrong results. You can use 'allow_degenerated_sequence=True' followed by a call of method .regenerated() for correcting this.
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> Seq2((Matrix([Integer(2)]), Matrix([Integer(3)])), vector([Integer(1)]), vector([Integer(1)])) Traceback (most recent call last): ... DegeneratedSequenceError: degenerated sequence: mu[0]*right != right. Using such a sequence might lead to wrong results. You can use 'allow_degenerated_sequence=True' followed by a call of method .regenerated() for correcting this.
- class sage.combinat.regular_sequence.RecurrenceParser(k, coefficient_ring)[source]¶
Bases:
object
A parser for recurrence relations that allow the construction of a \(k\)-linear representation for the sequence satisfying these recurrence relations.
This is used by
RegularSequenceRing.from_recurrence()
to construct aRegularSequence
.- ind(M, m, ll, uu)[source]¶
Determine the index operator corresponding to the recursive sequence as defined in [HKL2022].
INPUT:
M
,m
– parameters of the recursive sequences, see [HKL2022], Definition 3.1ll
,uu
– parameters of the resulting linear representation, see [HKL2022], Theorem A
OUTPUT:
A dictionary which maps both row numbers to subsequence parameters and vice versa, i.e.,
ind[i]
– a pair(j, d)
representing the sequence \(x(k^j n + d)\) in the \(i\)-th component (0-based) of the resulting linear representationind[(j, d)]
– the (0-based) row number of the sequence \(x(k^j n + d)\) in the linear representation
EXAMPLES:
sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: RP.ind(3, 1, -3, 3) {(0, 0): 0, (1, -1): 3, (1, -2): 2, (1, -3): 1, (1, 0): 4, (1, 1): 5, (1, 2): 6, (1, 3): 7, (2, -1): 10, (2, -2): 9, (2, -3): 8, (2, 0): 11, (2, 1): 12, (2, 2): 13, (2, 3): 14, (2, 4): 15, (2, 5): 16, 0: (0, 0), 1: (1, -3), 10: (2, -1), 11: (2, 0), 12: (2, 1), 13: (2, 2), 14: (2, 3), 15: (2, 4), 16: (2, 5), 2: (1, -2), 3: (1, -1), 4: (1, 0), 5: (1, 1), 6: (1, 2), 7: (1, 3), 8: (2, -3), 9: (2, -2)}
>>> from sage.all import * >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> RP.ind(Integer(3), Integer(1), -Integer(3), Integer(3)) {(0, 0): 0, (1, -1): 3, (1, -2): 2, (1, -3): 1, (1, 0): 4, (1, 1): 5, (1, 2): 6, (1, 3): 7, (2, -1): 10, (2, -2): 9, (2, -3): 8, (2, 0): 11, (2, 1): 12, (2, 2): 13, (2, 3): 14, (2, 4): 15, (2, 5): 16, 0: (0, 0), 1: (1, -3), 10: (2, -1), 11: (2, 0), 12: (2, 1), 13: (2, 2), 14: (2, 3), 15: (2, 4), 16: (2, 5), 2: (1, -2), 3: (1, -1), 4: (1, 0), 5: (1, 1), 6: (1, 2), 7: (1, 3), 8: (2, -3), 9: (2, -2)}
- left(recurrence_rules)[source]¶
Construct the vector
left
of the linear representation of recursive sequences.INPUT:
recurrence_rules
– a namedtuple generated byparameters()
; it only needs to contain a fielddim
(a positive integer)
OUTPUT: a vector
EXAMPLES:
sage: from collections import namedtuple sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: RRD = namedtuple('recurrence_rules_dim', ....: ['dim', 'inhomogeneities']) sage: recurrence_rules = RRD(dim=5, inhomogeneities={}) sage: RP.left(recurrence_rules) (1, 0, 0, 0, 0)
>>> from sage.all import * >>> from collections import namedtuple >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> RRD = namedtuple('recurrence_rules_dim', ... ['dim', 'inhomogeneities']) >>> recurrence_rules = RRD(dim=Integer(5), inhomogeneities={}) >>> RP.left(recurrence_rules) (1, 0, 0, 0, 0)
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: RRD = namedtuple('recurrence_rules_dim', ....: ['M', 'm', 'll', 'uu', 'dim', 'inhomogeneities']) sage: recurrence_rules = RRD(M=3, m=2, ll=0, uu=9, dim=5, ....: inhomogeneities={0: Seq2.one_hadamard()}) sage: RP.left(recurrence_rules) (1, 0, 0, 0, 0, 0, 0, 0)
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> RRD = namedtuple('recurrence_rules_dim', ... ['M', 'm', 'll', 'uu', 'dim', 'inhomogeneities']) >>> recurrence_rules = RRD(M=Integer(3), m=Integer(2), ll=Integer(0), uu=Integer(9), dim=Integer(5), ... inhomogeneities={Integer(0): Seq2.one_hadamard()}) >>> RP.left(recurrence_rules) (1, 0, 0, 0, 0, 0, 0, 0)
- matrix(recurrence_rules, rem, correct_offset=True)[source]¶
Construct the matrix for remainder
rem
of the linear representation of the sequence represented byrecurrence_rules
.INPUT:
recurrence_rules
– a namedtuple generated byparameters()
rem
– integer between \(0\) and \(k - 1\)correct_offset
– boolean (default:True
); ifTrue
, then the resulting linear representation has no offset. See [HKL2022] for more information.
OUTPUT: a matrix
EXAMPLES:
The following example illustrates how the coefficients in the right-hand sides of the recurrence relations correspond to the entries of the matrices.
sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: var('n') n sage: function('f') f sage: M, m, coeffs, initial_values = RP.parse_recurrence([ ....: f(8*n) == -1*f(2*n - 1) + 1*f(2*n + 1), ....: f(8*n + 1) == -11*f(2*n - 1) + 10*f(2*n) + 11*f(2*n + 1), ....: f(8*n + 2) == -21*f(2*n - 1) + 20*f(2*n) + 21*f(2*n + 1), ....: f(8*n + 3) == -31*f(2*n - 1) + 30*f(2*n) + 31*f(2*n + 1), ....: f(8*n + 4) == -41*f(2*n - 1) + 40*f(2*n) + 41*f(2*n + 1), ....: f(8*n + 5) == -51*f(2*n - 1) + 50*f(2*n) + 51*f(2*n + 1), ....: f(8*n + 6) == -61*f(2*n - 1) + 60*f(2*n) + 61*f(2*n + 1), ....: f(8*n + 7) == -71*f(2*n - 1) + 70*f(2*n) + 71*f(2*n + 1), ....: f(0) == 0, f(1) == 1, f(2) == 2, f(3) == 3, f(4) == 4, ....: f(5) == 5, f(6) == 6, f(7) == 7], f, n) sage: rules = RP.parameters( ....: M, m, coeffs, initial_values, 0) sage: RP.matrix(rules, 0, False) [ 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 -51 50 51 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 -61 60 61 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 -71 70 71 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -1 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -11 10 11 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -21 20 21 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -31 30 31 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -41 40 41 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -51 50 51 0 0 0 0 0 0 0 0 0 0 0] sage: RP.matrix(rules, 1, False) [ 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1] [ 0 0 0 -11 10 11 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -21 20 21 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -31 30 31 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -41 40 41 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -51 50 51 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -61 60 61 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -71 70 71 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 -1 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 -11 10 11 0 0 0 0 0 0 0 0 0]
>>> from sage.all import * >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> var('n') n >>> function('f') f >>> M, m, coeffs, initial_values = RP.parse_recurrence([ ... f(Integer(8)*n) == -Integer(1)*f(Integer(2)*n - Integer(1)) + Integer(1)*f(Integer(2)*n + Integer(1)), ... f(Integer(8)*n + Integer(1)) == -Integer(11)*f(Integer(2)*n - Integer(1)) + Integer(10)*f(Integer(2)*n) + Integer(11)*f(Integer(2)*n + Integer(1)), ... f(Integer(8)*n + Integer(2)) == -Integer(21)*f(Integer(2)*n - Integer(1)) + Integer(20)*f(Integer(2)*n) + Integer(21)*f(Integer(2)*n + Integer(1)), ... f(Integer(8)*n + Integer(3)) == -Integer(31)*f(Integer(2)*n - Integer(1)) + Integer(30)*f(Integer(2)*n) + Integer(31)*f(Integer(2)*n + Integer(1)), ... f(Integer(8)*n + Integer(4)) == -Integer(41)*f(Integer(2)*n - Integer(1)) + Integer(40)*f(Integer(2)*n) + Integer(41)*f(Integer(2)*n + Integer(1)), ... f(Integer(8)*n + Integer(5)) == -Integer(51)*f(Integer(2)*n - Integer(1)) + Integer(50)*f(Integer(2)*n) + Integer(51)*f(Integer(2)*n + Integer(1)), ... f(Integer(8)*n + Integer(6)) == -Integer(61)*f(Integer(2)*n - Integer(1)) + Integer(60)*f(Integer(2)*n) + Integer(61)*f(Integer(2)*n + Integer(1)), ... f(Integer(8)*n + Integer(7)) == -Integer(71)*f(Integer(2)*n - Integer(1)) + Integer(70)*f(Integer(2)*n) + Integer(71)*f(Integer(2)*n + Integer(1)), ... f(Integer(0)) == Integer(0), f(Integer(1)) == Integer(1), f(Integer(2)) == Integer(2), f(Integer(3)) == Integer(3), f(Integer(4)) == Integer(4), ... f(Integer(5)) == Integer(5), f(Integer(6)) == Integer(6), f(Integer(7)) == Integer(7)], f, n) >>> rules = RP.parameters( ... M, m, coeffs, initial_values, Integer(0)) >>> RP.matrix(rules, Integer(0), False) [ 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 -51 50 51 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 -61 60 61 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 -71 70 71 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -1 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -11 10 11 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -21 20 21 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -31 30 31 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -41 40 41 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -51 50 51 0 0 0 0 0 0 0 0 0 0 0] >>> RP.matrix(rules, Integer(1), False) [ 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1] [ 0 0 0 -11 10 11 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -21 20 21 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -31 30 31 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -41 40 41 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -51 50 51 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -61 60 61 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 -71 70 71 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 -1 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 -11 10 11 0 0 0 0 0 0 0 0 0]
Stern–Brocot Sequence:
sage: SB_rules = RP.parameters( ....: 1, 0, {(0, 0): 1, (1, 0): 1, (1, 1): 1}, ....: {0: 0, 1: 1, 2: 1}, 0) sage: RP.matrix(SB_rules, 0) [1 0 0] [1 1 0] [0 1 0] sage: RP.matrix(SB_rules, 1) [1 1 0] [0 1 0] [0 1 1]
>>> from sage.all import * >>> SB_rules = RP.parameters( ... Integer(1), Integer(0), {(Integer(0), Integer(0)): Integer(1), (Integer(1), Integer(0)): Integer(1), (Integer(1), Integer(1)): Integer(1)}, ... {Integer(0): Integer(0), Integer(1): Integer(1), Integer(2): Integer(1)}, Integer(0)) >>> RP.matrix(SB_rules, Integer(0)) [1 0 0] [1 1 0] [0 1 0] >>> RP.matrix(SB_rules, Integer(1)) [1 1 0] [0 1 0] [0 1 1]
Number of Unbordered Factors in the Thue–Morse Sequence:
sage: M, m, coeffs, initial_values = RP.parse_recurrence([ ....: f(8*n) == 2*f(4*n), ....: f(8*n + 1) == f(4*n + 1), ....: f(8*n + 2) == f(4*n + 1) + f(4*n + 3), ....: f(8*n + 3) == -f(4*n + 1) + f(4*n + 2), ....: f(8*n + 4) == 2*f(4*n + 2), ....: f(8*n + 5) == f(4*n + 3), ....: f(8*n + 6) == -f(4*n + 1) + f(4*n + 2) + f(4*n + 3), ....: f(8*n + 7) == 2*f(4*n + 1) + f(4*n + 3), ....: f(0) == 1, f(1) == 2, f(2) == 2, f(3) == 4, f(4) == 2, ....: f(5) == 4, f(6) == 6, f(7) == 0, f(8) == 4, f(9) == 4, ....: f(10) == 4, f(11) == 4, f(12) == 12, f(13) == 0, f(14) == 4, ....: f(15) == 4, f(16) == 8, f(17) == 4, f(18) == 8, f(19) == 0, ....: f(20) == 8, f(21) == 4, f(22) == 4, f(23) == 8], f, n) sage: UB_rules = RP.parameters( ....: M, m, coeffs, initial_values, 3) sage: RP.matrix(UB_rules, 0) [ 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 2 0 0 0 0 0 0 0 0 0 -1 0 0] [ 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 1 0 1 0 0 0 0 0 0 -4 0 0] [ 0 0 0 0 -1 1 0 0 0 0 0 0 0 4 2 0] [ 0 0 0 0 0 2 0 0 0 0 0 0 0 -2 0 0] [ 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 -1 1 1 0 0 0 0 0 0 2 2 0] [ 0 0 0 0 2 0 1 0 0 0 0 0 0 -8 -4 -4] [ 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0] sage: RP.matrix(UB_rules, 1) [ 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 2 0 0 0 0 0 0 0 -2 0 0] [ 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 -1 1 1 0 0 0 0 0 0 2 2 0] [ 0 0 0 0 2 0 1 0 0 0 0 0 0 -8 -4 -4] [ 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 -1 1 0 0 0 2 0 0] [ 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
>>> from sage.all import * >>> M, m, coeffs, initial_values = RP.parse_recurrence([ ... f(Integer(8)*n) == Integer(2)*f(Integer(4)*n), ... f(Integer(8)*n + Integer(1)) == f(Integer(4)*n + Integer(1)), ... f(Integer(8)*n + Integer(2)) == f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(3)), ... f(Integer(8)*n + Integer(3)) == -f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(2)), ... f(Integer(8)*n + Integer(4)) == Integer(2)*f(Integer(4)*n + Integer(2)), ... f(Integer(8)*n + Integer(5)) == f(Integer(4)*n + Integer(3)), ... f(Integer(8)*n + Integer(6)) == -f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(2)) + f(Integer(4)*n + Integer(3)), ... f(Integer(8)*n + Integer(7)) == Integer(2)*f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(3)), ... f(Integer(0)) == Integer(1), f(Integer(1)) == Integer(2), f(Integer(2)) == Integer(2), f(Integer(3)) == Integer(4), f(Integer(4)) == Integer(2), ... f(Integer(5)) == Integer(4), f(Integer(6)) == Integer(6), f(Integer(7)) == Integer(0), f(Integer(8)) == Integer(4), f(Integer(9)) == Integer(4), ... f(Integer(10)) == Integer(4), f(Integer(11)) == Integer(4), f(Integer(12)) == Integer(12), f(Integer(13)) == Integer(0), f(Integer(14)) == Integer(4), ... f(Integer(15)) == Integer(4), f(Integer(16)) == Integer(8), f(Integer(17)) == Integer(4), f(Integer(18)) == Integer(8), f(Integer(19)) == Integer(0), ... f(Integer(20)) == Integer(8), f(Integer(21)) == Integer(4), f(Integer(22)) == Integer(4), f(Integer(23)) == Integer(8)], f, n) >>> UB_rules = RP.parameters( ... M, m, coeffs, initial_values, Integer(3)) >>> RP.matrix(UB_rules, Integer(0)) [ 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 2 0 0 0 0 0 0 0 0 0 -1 0 0] [ 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 1 0 1 0 0 0 0 0 0 -4 0 0] [ 0 0 0 0 -1 1 0 0 0 0 0 0 0 4 2 0] [ 0 0 0 0 0 2 0 0 0 0 0 0 0 -2 0 0] [ 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 -1 1 1 0 0 0 0 0 0 2 2 0] [ 0 0 0 0 2 0 1 0 0 0 0 0 0 -8 -4 -4] [ 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0] >>> RP.matrix(UB_rules, Integer(1)) [ 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 2 0 0 0 0 0 0 0 -2 0 0] [ 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 -1 1 1 0 0 0 0 0 0 2 2 0] [ 0 0 0 0 2 0 1 0 0 0 0 0 0 -8 -4 -4] [ 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 -1 1 0 0 0 2 0 0] [ 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0] [ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
- parameters(M, m, coeffs, initial_values, offset=0, inhomogeneities={})[source]¶
Determine parameters from recurrence relations as admissible in
RegularSequenceRing.from_recurrence()
.INPUT:
All parameters are explained in the high-level method
RegularSequenceRing.from_recurrence()
.OUTPUT: a namedtuple
recurrence_rules
consisting ofM
,m
,l
,u
,offset
– parameters of the recursive sequences, see [HKL2022], Definition 3.1ll
,uu
,n1
,dim
– parameters and dimension of the resulting linear representation, see [HKL2022], Theorem Acoeffs
– dictionary mapping(r, j)
to the coefficients \(c_{r, j}\) as given in [HKL2022], Equation (3.1). Ifcoeffs[(r, j)]
is not given for somer
andj
, then it is assumed to be zero.initial_values
– dictionary mapping integersn
to then
-th value of the sequenceinhomogeneities
– dictionary mapping integersr
to the inhomogeneity \(g_r\) as given in [HKL2022], Corollary D
EXAMPLES:
sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: RP.parameters(2, 1, ....: {(0, -2): 3, (0, 0): 1, (0, 1): 2, (1, -2): 6, (1, 0): 4, ....: (1, 1): 5, (2, -2): 9, (2, 0): 7, (2, 1): 8, (3, -2): 12, ....: (3, 0): 10, (3, 1): 11}, {0: 1, 1: 2, 2: 1, 3: 4}, 0, {0: 1}) recurrence_rules(M=2, m=1, l=-2, u=1, ll=-6, uu=3, dim=14, coeffs={(0, -2): 3, (0, 0): 1, (0, 1): 2, (1, -2): 6, (1, 0): 4, (1, 1): 5, (2, -2): 9, (2, 0): 7, (2, 1): 8, (3, -2): 12, (3, 0): 10, (3, 1): 11}, initial_values={0: 1, 1: 2, 2: 1, 3: 4, 4: 13, 5: 30, 6: 48, 7: 66, 8: 77, 9: 208, 10: 340, 11: 472, 12: 220, 13: 600, -6: 0, -5: 0, -4: 0, -3: 0, -2: 0, -1: 0}, offset=1, n1=3, inhomogeneities={0: 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...})
>>> from sage.all import * >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> RP.parameters(Integer(2), Integer(1), ... {(Integer(0), -Integer(2)): Integer(3), (Integer(0), Integer(0)): Integer(1), (Integer(0), Integer(1)): Integer(2), (Integer(1), -Integer(2)): Integer(6), (Integer(1), Integer(0)): Integer(4), ... (Integer(1), Integer(1)): Integer(5), (Integer(2), -Integer(2)): Integer(9), (Integer(2), Integer(0)): Integer(7), (Integer(2), Integer(1)): Integer(8), (Integer(3), -Integer(2)): Integer(12), ... (Integer(3), Integer(0)): Integer(10), (Integer(3), Integer(1)): Integer(11)}, {Integer(0): Integer(1), Integer(1): Integer(2), Integer(2): Integer(1), Integer(3): Integer(4)}, Integer(0), {Integer(0): Integer(1)}) recurrence_rules(M=2, m=1, l=-2, u=1, ll=-6, uu=3, dim=14, coeffs={(0, -2): 3, (0, 0): 1, (0, 1): 2, (1, -2): 6, (1, 0): 4, (1, 1): 5, (2, -2): 9, (2, 0): 7, (2, 1): 8, (3, -2): 12, (3, 0): 10, (3, 1): 11}, initial_values={0: 1, 1: 2, 2: 1, 3: 4, 4: 13, 5: 30, 6: 48, 7: 66, 8: 77, 9: 208, 10: 340, 11: 472, 12: 220, 13: 600, -6: 0, -5: 0, -4: 0, -3: 0, -2: 0, -1: 0}, offset=1, n1=3, inhomogeneities={0: 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...})
- parse_direct_arguments(M, m, coeffs, initial_values)[source]¶
Check whether the direct arguments as admissible in
RegularSequenceRing.from_recurrence()
are valid.INPUT:
All parameters are explained in the high-level method
RegularSequenceRing.from_recurrence()
.OUTPUT: a tuple consisting of the input parameters
EXAMPLES:
sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: RP.parse_direct_arguments(2, 1, ....: {(0, -2): 3, (0, 0): 1, (0, 1): 2, ....: (1, -2): 6, (1, 0): 4, (1, 1): 5, ....: (2, -2): 9, (2, 0): 7, (2, 1): 8, ....: (3, -2): 12, (3, 0): 10, (3, 1): 11}, ....: {0: 1, 1: 2, 2: 1}) (2, 1, {(0, -2): 3, (0, 0): 1, (0, 1): 2, (1, -2): 6, (1, 0): 4, (1, 1): 5, (2, -2): 9, (2, 0): 7, (2, 1): 8, (3, -2): 12, (3, 0): 10, (3, 1): 11}, {0: 1, 1: 2, 2: 1})
>>> from sage.all import * >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> RP.parse_direct_arguments(Integer(2), Integer(1), ... {(Integer(0), -Integer(2)): Integer(3), (Integer(0), Integer(0)): Integer(1), (Integer(0), Integer(1)): Integer(2), ... (Integer(1), -Integer(2)): Integer(6), (Integer(1), Integer(0)): Integer(4), (Integer(1), Integer(1)): Integer(5), ... (Integer(2), -Integer(2)): Integer(9), (Integer(2), Integer(0)): Integer(7), (Integer(2), Integer(1)): Integer(8), ... (Integer(3), -Integer(2)): Integer(12), (Integer(3), Integer(0)): Integer(10), (Integer(3), Integer(1)): Integer(11)}, ... {Integer(0): Integer(1), Integer(1): Integer(2), Integer(2): Integer(1)}) (2, 1, {(0, -2): 3, (0, 0): 1, (0, 1): 2, (1, -2): 6, (1, 0): 4, (1, 1): 5, (2, -2): 9, (2, 0): 7, (2, 1): 8, (3, -2): 12, (3, 0): 10, (3, 1): 11}, {0: 1, 1: 2, 2: 1})
Stern–Brocot Sequence:
sage: RP.parse_direct_arguments(1, 0, ....: {(0, 0): 1, (1, 0): 1, (1, 1): 1}, ....: {0: 0, 1: 1}) (1, 0, {(0, 0): 1, (1, 0): 1, (1, 1): 1}, {0: 0, 1: 1})
>>> from sage.all import * >>> RP.parse_direct_arguments(Integer(1), Integer(0), ... {(Integer(0), Integer(0)): Integer(1), (Integer(1), Integer(0)): Integer(1), (Integer(1), Integer(1)): Integer(1)}, ... {Integer(0): Integer(0), Integer(1): Integer(1)}) (1, 0, {(0, 0): 1, (1, 0): 1, (1, 1): 1}, {0: 0, 1: 1})
- parse_recurrence(equations, function, var)[source]¶
Parse recurrence relations as admissible in
RegularSequenceRing.from_recurrence()
.INPUT:
All parameters are explained in the high-level method
RegularSequenceRing.from_recurrence()
.OUTPUT: a tuple consisting of
M
,m
– seeRegularSequenceRing.from_recurrence()
coeffs
– seeRegularSequenceRing.from_recurrence()
initial_values
– seeRegularSequenceRing.from_recurrence()
EXAMPLES:
sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: var('n') n sage: function('f') f sage: RP.parse_recurrence([ ....: f(4*n) == f(2*n) + 2*f(2*n + 1) + 3*f(2*n - 2), ....: f(4*n + 1) == 4*f(2*n) + 5*f(2*n + 1) + 6*f(2*n - 2), ....: f(4*n + 2) == 7*f(2*n) + 8*f(2*n + 1) + 9*f(2*n - 2), ....: f(4*n + 3) == 10*f(2*n) + 11*f(2*n + 1) + 12*f(2*n - 2), ....: f(0) == 1, f(1) == 2, f(2) == 1], f, n) (2, 1, {(0, -2): 3, (0, 0): 1, (0, 1): 2, (1, -2): 6, (1, 0): 4, (1, 1): 5, (2, -2): 9, (2, 0): 7, (2, 1): 8, (3, -2): 12, (3, 0): 10, (3, 1): 11}, {0: 1, 1: 2, 2: 1})
>>> from sage.all import * >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> var('n') n >>> function('f') f >>> RP.parse_recurrence([ ... f(Integer(4)*n) == f(Integer(2)*n) + Integer(2)*f(Integer(2)*n + Integer(1)) + Integer(3)*f(Integer(2)*n - Integer(2)), ... f(Integer(4)*n + Integer(1)) == Integer(4)*f(Integer(2)*n) + Integer(5)*f(Integer(2)*n + Integer(1)) + Integer(6)*f(Integer(2)*n - Integer(2)), ... f(Integer(4)*n + Integer(2)) == Integer(7)*f(Integer(2)*n) + Integer(8)*f(Integer(2)*n + Integer(1)) + Integer(9)*f(Integer(2)*n - Integer(2)), ... f(Integer(4)*n + Integer(3)) == Integer(10)*f(Integer(2)*n) + Integer(11)*f(Integer(2)*n + Integer(1)) + Integer(12)*f(Integer(2)*n - Integer(2)), ... f(Integer(0)) == Integer(1), f(Integer(1)) == Integer(2), f(Integer(2)) == Integer(1)], f, n) (2, 1, {(0, -2): 3, (0, 0): 1, (0, 1): 2, (1, -2): 6, (1, 0): 4, (1, 1): 5, (2, -2): 9, (2, 0): 7, (2, 1): 8, (3, -2): 12, (3, 0): 10, (3, 1): 11}, {0: 1, 1: 2, 2: 1})
Stern–Brocot Sequence:
sage: RP.parse_recurrence([ ....: f(2*n) == f(n), f(2*n + 1) == f(n) + f(n + 1), ....: f(0) == 0, f(1) == 1], f, n) (1, 0, {(0, 0): 1, (1, 0): 1, (1, 1): 1}, {0: 0, 1: 1})
>>> from sage.all import * >>> RP.parse_recurrence([ ... f(Integer(2)*n) == f(n), f(Integer(2)*n + Integer(1)) == f(n) + f(n + Integer(1)), ... f(Integer(0)) == Integer(0), f(Integer(1)) == Integer(1)], f, n) (1, 0, {(0, 0): 1, (1, 0): 1, (1, 1): 1}, {0: 0, 1: 1})
- right(recurrence_rules)[source]¶
Construct the vector
right
of the linear representation of the sequence induced byrecurrence_rules
.INPUT:
recurrence_rules
– a namedtuple generated byparameters()
OUTPUT: a vector
- shifted_inhomogeneities(recurrence_rules)[source]¶
Return a dictionary of all needed shifted inhomogeneities as described in the proof of Corollary D in [HKL2022].
INPUT:
recurrence_rules
– a namedtuple generated byparameters()
OUTPUT:
A dictionary mapping \(r\) to the regular sequence \(\sum_i g_r(n + i)\) for \(g_r\) as given in [HKL2022], Corollary D, and \(i\) between \(\lfloor\ell'/k^{M}\rfloor\) and \(\lfloor (k^{M-1} - k^{m} + u')/k^{M}\rfloor + 1\); see [HKL2022], proof of Corollary D. The first blocks of the corresponding vector-valued sequence (obtained from its linear representation) correspond to the sequences \(g_r(n + i)\) where \(i\) is as in the sum above; the remaining blocks consist of other shifts which are required for the regular sequence.
EXAMPLES:
sage: from collections import namedtuple sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: Seq2 = RegularSequenceRing(2, ZZ) sage: S = Seq2((Matrix([[1, 0], [0, 1]]), Matrix([[1, 0], [1, 1]])), ....: left=vector([0, 1]), right=vector([1, 0])) sage: S 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... sage: RR = namedtuple('recurrence_rules', ....: ['M', 'm', 'll', 'uu', 'inhomogeneities']) sage: recurrence_rules = RR(M=3, m=0, ll=-14, uu=14, ....: inhomogeneities={0: S, 1: S}) sage: SI = RP.shifted_inhomogeneities(recurrence_rules) sage: SI {0: 2-regular sequence 4, 5, 7, 9, 11, 11, 11, 12, 13, 13, ..., 1: 2-regular sequence 4, 5, 7, 9, 11, 11, 11, 12, 13, 13, ...}
>>> from sage.all import * >>> from collections import namedtuple >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> S = Seq2((Matrix([[Integer(1), Integer(0)], [Integer(0), Integer(1)]]), Matrix([[Integer(1), Integer(0)], [Integer(1), Integer(1)]])), ... left=vector([Integer(0), Integer(1)]), right=vector([Integer(1), Integer(0)])) >>> S 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... >>> RR = namedtuple('recurrence_rules', ... ['M', 'm', 'll', 'uu', 'inhomogeneities']) >>> recurrence_rules = RR(M=Integer(3), m=Integer(0), ll=-Integer(14), uu=Integer(14), ... inhomogeneities={Integer(0): S, Integer(1): S}) >>> SI = RP.shifted_inhomogeneities(recurrence_rules) >>> SI {0: 2-regular sequence 4, 5, 7, 9, 11, 11, 11, 12, 13, 13, ..., 1: 2-regular sequence 4, 5, 7, 9, 11, 11, 11, 12, 13, 13, ...}
The first blocks of the corresponding vector-valued sequence correspond to the corresponding shifts of the inhomogeneity. In this particular case, there are no other blocks:
sage: lower = -2 sage: upper = 3 sage: SI[0].dimension() == S.dimension() * (upper - lower + 1) True sage: all( ....: Seq2( ....: SI[0].mu, ....: vector((i - lower)*[0, 0] + list(S.left) + (upper - i)*[0, 0]), ....: SI[0].right) ....: == S.subsequence(1, i) ....: for i in range(lower, upper+1)) True
>>> from sage.all import * >>> lower = -Integer(2) >>> upper = Integer(3) >>> SI[Integer(0)].dimension() == S.dimension() * (upper - lower + Integer(1)) True >>> all( ... Seq2( ... SI[Integer(0)].mu, ... vector((i - lower)*[Integer(0), Integer(0)] + list(S.left) + (upper - i)*[Integer(0), Integer(0)]), ... SI[Integer(0)].right) ... == S.subsequence(Integer(1), i) ... for i in range(lower, upper+Integer(1))) True
- v_eval_n(recurrence_rules, n)[source]¶
Return the vector \(v(n)\) as given in [HKL2022], Theorem A.
INPUT:
recurrence_rules
– a namedtuple generated byparameters()
n
– integer
OUTPUT: a vector
EXAMPLES:
Stern–Brocot Sequence:
sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: SB_rules = RP.parameters( ....: 1, 0, {(0, 0): 1, (1, 0): 1, (1, 1): 1}, ....: {0: 0, 1: 1, 2: 1}, 0) sage: RP.v_eval_n(SB_rules, 0) (0, 1, 1)
>>> from sage.all import * >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> SB_rules = RP.parameters( ... Integer(1), Integer(0), {(Integer(0), Integer(0)): Integer(1), (Integer(1), Integer(0)): Integer(1), (Integer(1), Integer(1)): Integer(1)}, ... {Integer(0): Integer(0), Integer(1): Integer(1), Integer(2): Integer(1)}, Integer(0)) >>> RP.v_eval_n(SB_rules, Integer(0)) (0, 1, 1)
- values(M, m, l, u, ll, coeffs, initial_values, last_value_needed, offset, inhomogeneities)[source]¶
Determine enough values of the corresponding recursive sequence by applying the recurrence relations given in
RegularSequenceRing.from_recurrence()
to the values given ininitial_values
.INPUT:
M
,m
,l
,u
,offset
– parameters of the recursive sequences, see [HKL2022], Definition 3.1ll
– parameter of the resulting linear representation, see [HKL2022], Theorem Acoeffs
– dictionary wherecoeffs[(r, j)]
is the coefficient \(c_{r,j}\) as given inRegularSequenceRing.from_recurrence()
. Ifcoeffs[(r, j)]
is not given for somer
andj
, then it is assumed to be zero.initial_values
– dictionary mapping integersn
to then
-th value of the sequencelast_value_needed
– last initial value which is needed to determine the linear representationinhomogeneities
– dictionary mapping integersr
to the inhomogeneity \(g_r\) as given in [HKL2022], Corollary D
OUTPUT:
A dictionary mapping integers
n
to then
-th value of the sequence for alln
up tolast_value_needed
.EXAMPLES:
Stern–Brocot Sequence:
sage: from sage.combinat.regular_sequence import RecurrenceParser sage: RP = RecurrenceParser(2, ZZ) sage: RP.values(M=1, m=0, l=0, u=1, ll=0, ....: coeffs={(0, 0): 1, (1, 0): 1, (1, 1): 1}, ....: initial_values={0: 0, 1: 1, 2: 1}, last_value_needed=20, ....: offset=0, inhomogeneities={}) {0: 0, 1: 1, 2: 1, 3: 2, 4: 1, 5: 3, 6: 2, 7: 3, 8: 1, 9: 4, 10: 3, 11: 5, 12: 2, 13: 5, 14: 3, 15: 4, 16: 1, 17: 5, 18: 4, 19: 7, 20: 3}
>>> from sage.all import * >>> from sage.combinat.regular_sequence import RecurrenceParser >>> RP = RecurrenceParser(Integer(2), ZZ) >>> RP.values(M=Integer(1), m=Integer(0), l=Integer(0), u=Integer(1), ll=Integer(0), ... coeffs={(Integer(0), Integer(0)): Integer(1), (Integer(1), Integer(0)): Integer(1), (Integer(1), Integer(1)): Integer(1)}, ... initial_values={Integer(0): Integer(0), Integer(1): Integer(1), Integer(2): Integer(1)}, last_value_needed=Integer(20), ... offset=Integer(0), inhomogeneities={}) {0: 0, 1: 1, 2: 1, 3: 2, 4: 1, 5: 3, 6: 2, 7: 3, 8: 1, 9: 4, 10: 3, 11: 5, 12: 2, 13: 5, 14: 3, 15: 4, 16: 1, 17: 5, 18: 4, 19: 7, 20: 3}
- class sage.combinat.regular_sequence.RegularSequence(parent, mu, left=None, right=None)[source]¶
Bases:
RecognizableSeries
A \(k\)-regular sequence.
INPUT:
parent
– an instance ofRegularSequenceRing
mu
– a family of square matrices, all of which have the same dimension. The indices of this family are \(0,...,k-1\).mu
may be a list or tuple of cardinality \(k\) as well. See alsomu()
.left
– (default:None
) a vector. When evaluating the sequence, this vector is multiplied from the left to the matrix product. IfNone
, then this multiplication is skipped.right
– (default:None
) a vector. When evaluating the sequence, this vector is multiplied from the right to the matrix product. IfNone
, then this multiplication is skipped.
When created via the parent
RegularSequenceRing
, then the following option is available.allow_degenerated_sequence
– boolean (default:False
); if set, then there will be no check if the input is a degenerated sequence (seeis_degenerated()
). Otherwise the input is checked and aDegeneratedSequenceError
is raised if such a sequence is detected.
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: S = Seq2((Matrix([[3, 0], [6, 1]]), Matrix([[0, 1], [-6, 5]])), ....: vector([1, 0]), vector([0, 1])); S 2-regular sequence 0, 1, 3, 5, 9, 11, 15, 19, 27, 29, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> S = Seq2((Matrix([[Integer(3), Integer(0)], [Integer(6), Integer(1)]]), Matrix([[Integer(0), Integer(1)], [-Integer(6), Integer(5)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])); S 2-regular sequence 0, 1, 3, 5, 9, 11, 15, 19, 27, 29, ...
We can access the coefficients of a sequence by
sage: S[5] 11
>>> from sage.all import * >>> S[Integer(5)] 11
or iterating over the first, say \(10\), by
sage: from itertools import islice sage: list(islice(S, 10)) [0, 1, 3, 5, 9, 11, 15, 19, 27, 29]
>>> from sage.all import * >>> from itertools import islice >>> list(islice(S, Integer(10))) [0, 1, 3, 5, 9, 11, 15, 19, 27, 29]
See also
- backward_differences(**kwds)[source]¶
Return the sequence of backward differences of this \(k\)-regular sequence.
INPUT:
minimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
Note
The coefficient to the index \(-1\) is \(0\).
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: C = Seq2((Matrix([[2, 0], [2, 1]]), Matrix([[0, 1], [-2, 3]])), ....: vector([1, 0]), vector([0, 1])) sage: C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... sage: C.backward_differences() 2-regular sequence 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> C = Seq2((Matrix([[Integer(2), Integer(0)], [Integer(2), Integer(1)]]), Matrix([[Integer(0), Integer(1)], [-Integer(2), Integer(3)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])) >>> C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... >>> C.backward_differences() 2-regular sequence 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...
sage: E = Seq2((Matrix([[0, 1], [0, 1]]), Matrix([[0, 0], [0, 1]])), ....: vector([1, 0]), vector([1, 1])) sage: E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... sage: E.backward_differences() 2-regular sequence 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, ...
>>> from sage.all import * >>> E = Seq2((Matrix([[Integer(0), Integer(1)], [Integer(0), Integer(1)]]), Matrix([[Integer(0), Integer(0)], [Integer(0), Integer(1)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(1), Integer(1)])) >>> E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... >>> E.backward_differences() 2-regular sequence 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, ...
- coefficient_of_n(n, **kwds)[source]¶
Return the \(n\)-th entry of this sequence.
INPUT:
n
– nonnegative integer
OUTPUT: an element of the universe of the sequence
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: S = Seq2((Matrix([[1, 0], [0, 1]]), Matrix([[0, -1], [1, 2]])), ....: left=vector([0, 1]), right=vector([1, 0])) sage: S[7] 3
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> S = Seq2((Matrix([[Integer(1), Integer(0)], [Integer(0), Integer(1)]]), Matrix([[Integer(0), -Integer(1)], [Integer(1), Integer(2)]])), ... left=vector([Integer(0), Integer(1)]), right=vector([Integer(1), Integer(0)])) >>> S[Integer(7)] 3
This is equivalent to:
sage: S.coefficient_of_n(7) 3
>>> from sage.all import * >>> S.coefficient_of_n(Integer(7)) 3
- convolution(*args, **kwds)[source]¶
Return the product of this \(k\)-regular sequence with
other
, where the multiplication is convolution of power series.The operator \(*\) is mapped to
convolution()
.INPUT:
other
– aRegularSequence
minimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
ALGORITHM:
See pdf attached to github pull request #35894 which contains a draft describing the details of the used algorithm.
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: E = Seq2((Matrix([[0, 1], [0, 1]]), Matrix([[0, 0], [0, 1]])), ....: vector([1, 0]), vector([1, 1])) sage: E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> E = Seq2((Matrix([[Integer(0), Integer(1)], [Integer(0), Integer(1)]]), Matrix([[Integer(0), Integer(0)], [Integer(0), Integer(1)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(1), Integer(1)])) >>> E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ...
We can build the convolution (in the sense of power-series) of \(E\) by itself via:
sage: E.convolution(E) 2-regular sequence 1, 0, 2, 0, 3, 0, 4, 0, 5, 0, ...
>>> from sage.all import * >>> E.convolution(E) 2-regular sequence 1, 0, 2, 0, 3, 0, 4, 0, 5, 0, ...
This is the same as using multiplication operator:
sage: E * E 2-regular sequence 1, 0, 2, 0, 3, 0, 4, 0, 5, 0, ...
>>> from sage.all import * >>> E * E 2-regular sequence 1, 0, 2, 0, 3, 0, 4, 0, 5, 0, ...
Building
partial_sums()
can also be seen as a convolution:sage: o = Seq2.one_hadamard() sage: E * o 2-regular sequence 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, ... sage: E * o == E.partial_sums(include_n=True) True
>>> from sage.all import * >>> o = Seq2.one_hadamard() >>> E * o 2-regular sequence 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, ... >>> E * o == E.partial_sums(include_n=True) True
- forward_differences(**kwds)[source]¶
Return the sequence of forward differences of this \(k\)-regular sequence.
INPUT:
minimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: C = Seq2((Matrix([[2, 0], [2, 1]]), Matrix([[0, 1], [-2, 3]])), ....: vector([1, 0]), vector([0, 1])) sage: C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... sage: C.forward_differences() 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> C = Seq2((Matrix([[Integer(2), Integer(0)], [Integer(2), Integer(1)]]), Matrix([[Integer(0), Integer(1)], [-Integer(2), Integer(3)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])) >>> C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... >>> C.forward_differences() 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...
sage: E = Seq2((Matrix([[0, 1], [0, 1]]), Matrix([[0, 0], [0, 1]])), ....: vector([1, 0]), vector([1, 1])) sage: E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... sage: E.forward_differences() 2-regular sequence -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, ...
>>> from sage.all import * >>> E = Seq2((Matrix([[Integer(0), Integer(1)], [Integer(0), Integer(1)]]), Matrix([[Integer(0), Integer(0)], [Integer(0), Integer(1)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(1), Integer(1)])) >>> E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... >>> E.forward_differences() 2-regular sequence -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, ...
- is_degenerated()[source]¶
Return whether this \(k\)-regular sequence is degenerated, i.e., whether this \(k\)-regular sequence does not satisfiy \(\mu[0] \mathit{right} = \mathit{right}\).
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: Seq2((Matrix([2]), Matrix([3])), vector([1]), vector([1])) # indirect doctest Traceback (most recent call last): ... DegeneratedSequenceError: degenerated sequence: mu[0]*right != right. Using such a sequence might lead to wrong results. You can use 'allow_degenerated_sequence=True' followed by a call of method .regenerated() for correcting this. sage: S = Seq2((Matrix([2]), Matrix([3])), vector([1]), vector([1]), ....: allow_degenerated_sequence=True) sage: S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... sage: S.is_degenerated() True
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> Seq2((Matrix([Integer(2)]), Matrix([Integer(3)])), vector([Integer(1)]), vector([Integer(1)])) # indirect doctest Traceback (most recent call last): ... DegeneratedSequenceError: degenerated sequence: mu[0]*right != right. Using such a sequence might lead to wrong results. You can use 'allow_degenerated_sequence=True' followed by a call of method .regenerated() for correcting this. >>> S = Seq2((Matrix([Integer(2)]), Matrix([Integer(3)])), vector([Integer(1)]), vector([Integer(1)]), ... allow_degenerated_sequence=True) >>> S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... >>> S.is_degenerated() True
sage: C = Seq2((Matrix([[2, 0], [2, 1]]), Matrix([[0, 1], [-2, 3]])), ....: vector([1, 0]), vector([0, 1])) sage: C.is_degenerated() False
>>> from sage.all import * >>> C = Seq2((Matrix([[Integer(2), Integer(0)], [Integer(2), Integer(1)]]), Matrix([[Integer(0), Integer(1)], [-Integer(2), Integer(3)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])) >>> C.is_degenerated() False
- partial_sums(*args, **kwds)[source]¶
Return the sequence of partial sums of this \(k\)-regular sequence. That is, the \(n\)-th entry of the result is the sum of the first \(n\) entries in the original sequence.
INPUT:
include_n
– boolean (default:False
); if set, then the \(n\)-th entry of the result is the sum of the entries up to index \(n\) (included)minimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: E = Seq2((Matrix([[0, 1], [0, 1]]), Matrix([[0, 0], [0, 1]])), ....: vector([1, 0]), vector([1, 1])) sage: E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... sage: E.partial_sums() 2-regular sequence 0, 1, 1, 2, 2, 3, 3, 4, 4, 5, ... sage: E.partial_sums(include_n=True) 2-regular sequence 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> E = Seq2((Matrix([[Integer(0), Integer(1)], [Integer(0), Integer(1)]]), Matrix([[Integer(0), Integer(0)], [Integer(0), Integer(1)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(1), Integer(1)])) >>> E 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... >>> E.partial_sums() 2-regular sequence 0, 1, 1, 2, 2, 3, 3, 4, 4, 5, ... >>> E.partial_sums(include_n=True) 2-regular sequence 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, ...
sage: C = Seq2((Matrix([[2, 0], [2, 1]]), Matrix([[0, 1], [-2, 3]])), ....: vector([1, 0]), vector([0, 1])) sage: C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... sage: C.partial_sums() 2-regular sequence 0, 0, 1, 3, 6, 10, 15, 21, 28, 36, ... sage: C.partial_sums(include_n=True) 2-regular sequence 0, 1, 3, 6, 10, 15, 21, 28, 36, 45, ...
>>> from sage.all import * >>> C = Seq2((Matrix([[Integer(2), Integer(0)], [Integer(2), Integer(1)]]), Matrix([[Integer(0), Integer(1)], [-Integer(2), Integer(3)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])) >>> C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... >>> C.partial_sums() 2-regular sequence 0, 0, 1, 3, 6, 10, 15, 21, 28, 36, ... >>> C.partial_sums(include_n=True) 2-regular sequence 0, 1, 3, 6, 10, 15, 21, 28, 36, 45, ...
The following linear representation of \(S\) is chosen badly (is degenerated, see
is_degenerated()
), as \(\mu(0)\) applied on \(\mathit{right}\) does not equal \(\mathit{right}\):sage: S = Seq2((Matrix([2]), Matrix([3])), vector([1]), vector([1]), ....: allow_degenerated_sequence=True) sage: S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ...
>>> from sage.all import * >>> S = Seq2((Matrix([Integer(2)]), Matrix([Integer(3)])), vector([Integer(1)]), vector([Integer(1)]), ... allow_degenerated_sequence=True) >>> S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ...
Therefore, building partial sums produces a wrong result:
sage: H = S.partial_sums(include_n=True, minimize=False) sage: H 2-regular sequence 1, 5, 16, 25, 62, 80, 98, 125, 274, 310, ... sage: H = S.partial_sums(minimize=False) sage: H 2-regular sequence 0, 2, 10, 16, 50, 62, 80, 98, 250, 274, ...
>>> from sage.all import * >>> H = S.partial_sums(include_n=True, minimize=False) >>> H 2-regular sequence 1, 5, 16, 25, 62, 80, 98, 125, 274, 310, ... >>> H = S.partial_sums(minimize=False) >>> H 2-regular sequence 0, 2, 10, 16, 50, 62, 80, 98, 250, 274, ...
We can
guess()
the correct representation:sage: from itertools import islice sage: L = []; ps = 0 sage: for s in islice(S, 110): ....: ps += s ....: L.append(ps) sage: G = Seq2.guess(lambda n: L[n]) sage: G 2-regular sequence 1, 4, 10, 19, 31, 49, 67, 94, 118, 154, ... sage: G.linear_representation() ((1, 0, 0, 0), Finite family {0: [ 0 1 0 0] [ 0 0 0 1] [ -5 5 1 0] [ 10 -17 0 8], 1: [ 0 0 1 0] [ -5 3 3 0] [ -5 0 6 0] [-30 21 10 0]}, (1, 1, 4, 1)) sage: G.minimized().dimension() == G.dimension() True
>>> from sage.all import * >>> from itertools import islice >>> L = []; ps = Integer(0) >>> for s in islice(S, Integer(110)): ... ps += s ... L.append(ps) >>> G = Seq2.guess(lambda n: L[n]) >>> G 2-regular sequence 1, 4, 10, 19, 31, 49, 67, 94, 118, 154, ... >>> G.linear_representation() ((1, 0, 0, 0), Finite family {0: [ 0 1 0 0] [ 0 0 0 1] [ -5 5 1 0] [ 10 -17 0 8], 1: [ 0 0 1 0] [ -5 3 3 0] [ -5 0 6 0] [-30 21 10 0]}, (1, 1, 4, 1)) >>> G.minimized().dimension() == G.dimension() True
Or we regenerate the sequence \(S\) first:
sage: S.regenerated().partial_sums(include_n=True, minimize=False) 2-regular sequence 1, 4, 10, 19, 31, 49, 67, 94, 118, 154, ... sage: S.regenerated().partial_sums(minimize=False) 2-regular sequence 0, 1, 4, 10, 19, 31, 49, 67, 94, 118, ...
>>> from sage.all import * >>> S.regenerated().partial_sums(include_n=True, minimize=False) 2-regular sequence 1, 4, 10, 19, 31, 49, 67, 94, 118, 154, ... >>> S.regenerated().partial_sums(minimize=False) 2-regular sequence 0, 1, 4, 10, 19, 31, 49, 67, 94, 118, ...
- regenerated(*args, **kwds)[source]¶
Return a \(k\)-regular sequence that satisfies \(\mu[0] \mathit{right} = \mathit{right}\) with the same values as this sequence.
INPUT:
minimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
ALGORITHM:
Theorem B of [HKL2022] with \(n_0 = 1\).
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ)
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ)
The following linear representation of \(S\) is chosen badly (is degenerated, see
is_degenerated()
), as \(\mu(0)\) applied on \(\mathit{right}\) does not equal \(\mathit{right}\):sage: S = Seq2((Matrix([2]), Matrix([3])), vector([1]), vector([1]), ....: allow_degenerated_sequence=True) sage: S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... sage: S.is_degenerated() True
>>> from sage.all import * >>> S = Seq2((Matrix([Integer(2)]), Matrix([Integer(3)])), vector([Integer(1)]), vector([Integer(1)]), ... allow_degenerated_sequence=True) >>> S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... >>> S.is_degenerated() True
However, we can regenerate the sequence \(S\):
sage: H = S.regenerated() sage: H 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... sage: H.linear_representation() ((1, 0), Finite family {0: [ 0 1] [-2 3], 1: [3 0] [6 0]}, (1, 1)) sage: H.is_degenerated() False
>>> from sage.all import * >>> H = S.regenerated() >>> H 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... >>> H.linear_representation() ((1, 0), Finite family {0: [ 0 1] [-2 3], 1: [3 0] [6 0]}, (1, 1)) >>> H.is_degenerated() False
- shift_left(b=1, **kwds)[source]¶
Return the sequence obtained by shifting this \(k\)-regular sequence \(b\) steps to the left.
INPUT:
b
– integerminimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
Note
If \(b\) is negative (i.e., actually a right-shift), then the coefficients when accessing negative indices are \(0\).
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: C = Seq2((Matrix([[2, 0], [0, 1]]), Matrix([[2, 1], [0, 1]])), ....: vector([1, 0]), vector([0, 1])); C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... sage: C.shift_left() 2-regular sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ... sage: C.shift_left(3) 2-regular sequence 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ... sage: C.shift_left(-2) 2-regular sequence 0, 0, 0, 1, 2, 3, 4, 5, 6, 7, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> C = Seq2((Matrix([[Integer(2), Integer(0)], [Integer(0), Integer(1)]]), Matrix([[Integer(2), Integer(1)], [Integer(0), Integer(1)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])); C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... >>> C.shift_left() 2-regular sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ... >>> C.shift_left(Integer(3)) 2-regular sequence 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ... >>> C.shift_left(-Integer(2)) 2-regular sequence 0, 0, 0, 1, 2, 3, 4, 5, 6, 7, ...
- shift_right(b=1, **kwds)[source]¶
Return the sequence obtained by shifting this \(k\)-regular sequence \(b\) steps to the right.
INPUT:
b
– integerminimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
Note
If \(b\) is positive (i.e., indeed a right-shift), then the coefficients when accessing negative indices are \(0\).
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: C = Seq2((Matrix([[2, 0], [0, 1]]), Matrix([[2, 1], [0, 1]])), ....: vector([1, 0]), vector([0, 1])); C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... sage: C.shift_right() 2-regular sequence 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, ... sage: C.shift_right(3) 2-regular sequence 0, 0, 0, 0, 1, 2, 3, 4, 5, 6, ... sage: C.shift_right(-2) 2-regular sequence 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> C = Seq2((Matrix([[Integer(2), Integer(0)], [Integer(0), Integer(1)]]), Matrix([[Integer(2), Integer(1)], [Integer(0), Integer(1)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])); C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... >>> C.shift_right() 2-regular sequence 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, ... >>> C.shift_right(Integer(3)) 2-regular sequence 0, 0, 0, 0, 1, 2, 3, 4, 5, 6, ... >>> C.shift_right(-Integer(2)) 2-regular sequence 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...
- subsequence(*args, **kwds)[source]¶
Return the subsequence with indices \(an+b\) of this \(k\)-regular sequence.
INPUT:
a
– nonnegative integerb
– integerAlternatively, this is allowed to be a dictionary \(b_j \mapsto c_j\). If so and applied on \(f(n)\), the result will be the sum of all \(c_j \cdot f(an+b_j)\).
minimize
– (default:None
) a boolean orNone
. IfTrue
, thenminimized()
is called after the operation, ifFalse
, then not. If this argument isNone
, then the default specified by the parent’sminimize_results
is used.
OUTPUT: a
RegularSequence
Note
If \(b\) is negative (i.e., right-shift), then the coefficients when accessing negative indices are \(0\).
EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ)
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ)
We consider the sequence \(C\) with \(C(n) = n\) and the following linear representation corresponding to the vector \((n, 1)\):
sage: C = Seq2((Matrix([[2, 0], [0, 1]]), Matrix([[2, 1], [0, 1]])), ....: vector([1, 0]), vector([0, 1])); C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ...
>>> from sage.all import * >>> C = Seq2((Matrix([[Integer(2), Integer(0)], [Integer(0), Integer(1)]]), Matrix([[Integer(2), Integer(1)], [Integer(0), Integer(1)]])), ... vector([Integer(1), Integer(0)]), vector([Integer(0), Integer(1)])); C 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ...
We now extract various subsequences of \(C\):
sage: C.subsequence(2, 0) 2-regular sequence 0, 2, 4, 6, 8, 10, 12, 14, 16, 18, ... sage: S31 = C.subsequence(3, 1); S31 2-regular sequence 1, 4, 7, 10, 13, 16, 19, 22, 25, 28, ... sage: S31.linear_representation() ((1, 0), Finite family {0: [ 0 1] [-2 3], 1: [ 6 -2] [10 -3]}, (1, 1)) sage: C.subsequence(3, 2) 2-regular sequence 2, 5, 8, 11, 14, 17, 20, 23, 26, 29, ...
>>> from sage.all import * >>> C.subsequence(Integer(2), Integer(0)) 2-regular sequence 0, 2, 4, 6, 8, 10, 12, 14, 16, 18, ... >>> S31 = C.subsequence(Integer(3), Integer(1)); S31 2-regular sequence 1, 4, 7, 10, 13, 16, 19, 22, 25, 28, ... >>> S31.linear_representation() ((1, 0), Finite family {0: [ 0 1] [-2 3], 1: [ 6 -2] [10 -3]}, (1, 1)) >>> C.subsequence(Integer(3), Integer(2)) 2-regular sequence 2, 5, 8, 11, 14, 17, 20, 23, 26, 29, ...
sage: Srs = C.subsequence(1, -1); Srs 2-regular sequence 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, ... sage: Srs.linear_representation() ((1, 0, 0), Finite family {0: [ 0 1 0] [-2 3 0] [-4 4 1], 1: [ -2 2 0] [ 0 0 1] [ 12 -12 5]}, (0, 0, 1))
>>> from sage.all import * >>> Srs = C.subsequence(Integer(1), -Integer(1)); Srs 2-regular sequence 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, ... >>> Srs.linear_representation() ((1, 0, 0), Finite family {0: [ 0 1 0] [-2 3 0] [-4 4 1], 1: [ -2 2 0] [ 0 0 1] [ 12 -12 5]}, (0, 0, 1))
We can build
backward_differences()
manually by passing a dictionary for the parameterb
:sage: Sbd = C.subsequence(1, {0: 1, -1: -1}); Sbd 2-regular sequence 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...
>>> from sage.all import * >>> Sbd = C.subsequence(Integer(1), {Integer(0): Integer(1), -Integer(1): -Integer(1)}); Sbd 2-regular sequence 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...
- transposed(allow_degenerated_sequence=False)[source]¶
Return the transposed sequence.
INPUT:
allow_degenerated_sequence
– boolean (default:False
); if set, then there will be no check if the transposed sequence is a degenerated sequence (seeis_degenerated()
). Otherwise the transposed sequence is checked and aDegeneratedSequenceError
is raised if such a sequence is detected.
OUTPUT: a
RegularSequence
Each of the matrices in
mu
is transposed. Additionally the vectorsleft
andright
are switched.EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: U = Seq2((Matrix([[3, 2], [0, 1]]), Matrix([[2, 0], [1, 3]])), ....: left=vector([0, 1]), right=vector([1, 0]), ....: allow_degenerated_sequence=True) sage: U.is_degenerated() True sage: Ut = U.transposed() sage: Ut.linear_representation() ((1, 0), Finite family {0: [3 0] [2 1], 1: [2 1] [0 3]}, (0, 1)) sage: Ut.is_degenerated() False sage: Ut.transposed() Traceback (most recent call last): ... DegeneratedSequenceError: degenerated sequence: mu[0]*right != right. Using such a sequence might lead to wrong results. You can use 'allow_degenerated_sequence=True' followed by a call of method .regenerated() for correcting this. sage: Utt = Ut.transposed(allow_degenerated_sequence=True) sage: Utt.is_degenerated() True
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> U = Seq2((Matrix([[Integer(3), Integer(2)], [Integer(0), Integer(1)]]), Matrix([[Integer(2), Integer(0)], [Integer(1), Integer(3)]])), ... left=vector([Integer(0), Integer(1)]), right=vector([Integer(1), Integer(0)]), ... allow_degenerated_sequence=True) >>> U.is_degenerated() True >>> Ut = U.transposed() >>> Ut.linear_representation() ((1, 0), Finite family {0: [3 0] [2 1], 1: [2 1] [0 3]}, (0, 1)) >>> Ut.is_degenerated() False >>> Ut.transposed() Traceback (most recent call last): ... DegeneratedSequenceError: degenerated sequence: mu[0]*right != right. Using such a sequence might lead to wrong results. You can use 'allow_degenerated_sequence=True' followed by a call of method .regenerated() for correcting this. >>> Utt = Ut.transposed(allow_degenerated_sequence=True) >>> Utt.is_degenerated() True
See also
- class sage.combinat.regular_sequence.RegularSequenceRing(k, *args, **kwds)[source]¶
Bases:
RecognizableSeriesSpace
The space of \(k\)-regular Sequences over the given
coefficient_ring
.INPUT:
k
– integer at least \(2\) specifying the basecoefficient_ring
– a (semi-)ringcategory
– (default:None
) the category of this space
EXAMPLES:
sage: RegularSequenceRing(2, ZZ) Space of 2-regular sequences over Integer Ring sage: RegularSequenceRing(3, ZZ) Space of 3-regular sequences over Integer Ring
>>> from sage.all import * >>> RegularSequenceRing(Integer(2), ZZ) Space of 2-regular sequences over Integer Ring >>> RegularSequenceRing(Integer(3), ZZ) Space of 3-regular sequences over Integer Ring
See also
- Element[source]¶
alias of
RegularSequence
- from_recurrence(*args, **kwds)[source]¶
Construct the unique \(k\)-regular sequence which fulfills the given recurrence relations and initial values. The recurrence relations have to have the specific shape of \(k\)-recursive sequences as described in [HKL2022], and are either given as symbolic equations, e.g.,
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: var('n') n sage: function('f') f sage: Seq2.from_recurrence([ ....: f(2*n) == 2*f(n), f(2*n + 1) == 3*f(n) + 4*f(n - 1), ....: f(0) == 0, f(1) == 1], f, n) 2-regular sequence 0, 0, 0, 1, 2, 3, 4, 10, 6, 17, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> var('n') n >>> function('f') f >>> Seq2.from_recurrence([ ... f(Integer(2)*n) == Integer(2)*f(n), f(Integer(2)*n + Integer(1)) == Integer(3)*f(n) + Integer(4)*f(n - Integer(1)), ... f(Integer(0)) == Integer(0), f(Integer(1)) == Integer(1)], f, n) 2-regular sequence 0, 0, 0, 1, 2, 3, 4, 10, 6, 17, ...
or via the parameters of the \(k\)-recursive sequence as described in the input block below:
sage: Seq2.from_recurrence(M=1, m=0, ....: coeffs={(0, 0): 2, (1, 0): 3, (1, -1): 4}, ....: initial_values={0: 0, 1: 1}) 2-regular sequence 0, 0, 0, 1, 2, 3, 4, 10, 6, 17, ...
>>> from sage.all import * >>> Seq2.from_recurrence(M=Integer(1), m=Integer(0), ... coeffs={(Integer(0), Integer(0)): Integer(2), (Integer(1), Integer(0)): Integer(3), (Integer(1), -Integer(1)): Integer(4)}, ... initial_values={Integer(0): Integer(0), Integer(1): Integer(1)}) 2-regular sequence 0, 0, 0, 1, 2, 3, 4, 10, 6, 17, ...
INPUT:
Positional arguments:
If the recurrence relations are represented by symbolic equations, then the following arguments are required:
equations
– list of equations where the elements have either the form\(f(k^M n + r) = c_{r,l} f(k^m n + l) + c_{r,l + 1} f(k^m n + l + 1) + ... + c_{r,u} f(k^m n + u)\) for some integers \(0 \leq r < k^M\), \(M > m \geq 0\) and \(l \leq u\), and some coefficients \(c_{r,j}\) from the (semi)ring
coefficients
of the correspondingRegularSequenceRing
, valid for all integers \(n \geq \text{offset}\) for some integer \(\text{offset} \geq \max(-l/k^m, 0)\) (default:0
), and there is an equation of this form (with the same parameters \(M\) and \(m\)) for all \(r\)
or the form
f(k) == t
for some integerk
and somet
from the (semi)ringcoefficient_ring
.
The recurrence relations above uniquely determine a \(k\)-regular sequence; see [HKL2022] for further information.
function
– symbolic functionf
occurring in the equationsvar
– symbolic variable (n
in the above description ofequations
)
The following second representation of the recurrence relations is particularly useful for cases where
coefficient_ring
is not compatible withsage.symbolic.ring.SymbolicRing
. Then the following arguments are required:M
– parameter of the recursive sequences, see [HKL2022], Definition 3.1, as well as in the description ofequations
abovem
– parameter of the recursive sequences, see [HKL2022], Definition 3.1, as well as in the description ofequations
abovecoeffs
– dictionary wherecoeffs[(r, j)]
is the coefficient \(c_{r,j}\) as given in the description ofequations
above. Ifcoeffs[(r, j)]
is not given for somer
andj
, then it is assumed to be zero.initial_values
– dictionary mapping integersn
to then
-th value of the sequence
Optional keyword-only argument:
offset
– integer (default: \(0\)); see explanation ofequations
aboveinhomogeneities
– (default:{}
) a dictionary mapping integersr
to the inhomogeneity \(g_r\) as given in [HKL2022], Corollary D. All inhomogeneities have to be regular sequences fromself
or elements ofcoefficient_ring
.
OUTPUT: a
RegularSequence
EXAMPLES:
Stern–Brocot Sequence:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: var('n') n sage: function('f') f sage: SB = Seq2.from_recurrence([ ....: f(2*n) == f(n), f(2*n + 1) == f(n) + f(n + 1), ....: f(0) == 0, f(1) == 1], f, n) sage: SB 2-regular sequence 0, 1, 1, 2, 1, 3, 2, 3, 1, 4, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> var('n') n >>> function('f') f >>> SB = Seq2.from_recurrence([ ... f(Integer(2)*n) == f(n), f(Integer(2)*n + Integer(1)) == f(n) + f(n + Integer(1)), ... f(Integer(0)) == Integer(0), f(Integer(1)) == Integer(1)], f, n) >>> SB 2-regular sequence 0, 1, 1, 2, 1, 3, 2, 3, 1, 4, ...
Number of Odd Entries in Pascal’s Triangle:
sage: Seq2.from_recurrence([ ....: f(2*n) == 3*f(n), f(2*n + 1) == 2*f(n) + f(n + 1), ....: f(0) == 0, f(1) == 1], f, n) 2-regular sequence 0, 1, 3, 5, 9, 11, 15, 19, 27, 29, ...
>>> from sage.all import * >>> Seq2.from_recurrence([ ... f(Integer(2)*n) == Integer(3)*f(n), f(Integer(2)*n + Integer(1)) == Integer(2)*f(n) + f(n + Integer(1)), ... f(Integer(0)) == Integer(0), f(Integer(1)) == Integer(1)], f, n) 2-regular sequence 0, 1, 3, 5, 9, 11, 15, 19, 27, 29, ...
Number of Unbordered Factors in the Thue–Morse Sequence:
sage: UB = Seq2.from_recurrence([ ....: f(8*n) == 2*f(4*n), ....: f(8*n + 1) == f(4*n + 1), ....: f(8*n + 2) == f(4*n + 1) + f(4*n + 3), ....: f(8*n + 3) == -f(4*n + 1) + f(4*n + 2), ....: f(8*n + 4) == 2*f(4*n + 2), ....: f(8*n + 5) == f(4*n + 3), ....: f(8*n + 6) == -f(4*n + 1) + f(4*n + 2) + f(4*n + 3), ....: f(8*n + 7) == 2*f(4*n + 1) + f(4*n + 3), ....: f(0) == 1, f(1) == 2, f(2) == 2, f(3) == 4, f(4) == 2, ....: f(5) == 4, f(6) == 6, f(7) == 0, f(8) == 4, f(9) == 4, ....: f(10) == 4, f(11) == 4, f(12) == 12, f(13) == 0, f(14) == 4, ....: f(15) == 4, f(16) == 8, f(17) == 4, f(18) == 8, f(19) == 0, ....: f(20) == 8, f(21) == 4, f(22) == 4, f(23) == 8], f, n, offset=3) sage: UB 2-regular sequence 1, 2, 2, 4, 2, 4, 6, 0, 4, 4, ...
>>> from sage.all import * >>> UB = Seq2.from_recurrence([ ... f(Integer(8)*n) == Integer(2)*f(Integer(4)*n), ... f(Integer(8)*n + Integer(1)) == f(Integer(4)*n + Integer(1)), ... f(Integer(8)*n + Integer(2)) == f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(3)), ... f(Integer(8)*n + Integer(3)) == -f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(2)), ... f(Integer(8)*n + Integer(4)) == Integer(2)*f(Integer(4)*n + Integer(2)), ... f(Integer(8)*n + Integer(5)) == f(Integer(4)*n + Integer(3)), ... f(Integer(8)*n + Integer(6)) == -f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(2)) + f(Integer(4)*n + Integer(3)), ... f(Integer(8)*n + Integer(7)) == Integer(2)*f(Integer(4)*n + Integer(1)) + f(Integer(4)*n + Integer(3)), ... f(Integer(0)) == Integer(1), f(Integer(1)) == Integer(2), f(Integer(2)) == Integer(2), f(Integer(3)) == Integer(4), f(Integer(4)) == Integer(2), ... f(Integer(5)) == Integer(4), f(Integer(6)) == Integer(6), f(Integer(7)) == Integer(0), f(Integer(8)) == Integer(4), f(Integer(9)) == Integer(4), ... f(Integer(10)) == Integer(4), f(Integer(11)) == Integer(4), f(Integer(12)) == Integer(12), f(Integer(13)) == Integer(0), f(Integer(14)) == Integer(4), ... f(Integer(15)) == Integer(4), f(Integer(16)) == Integer(8), f(Integer(17)) == Integer(4), f(Integer(18)) == Integer(8), f(Integer(19)) == Integer(0), ... f(Integer(20)) == Integer(8), f(Integer(21)) == Integer(4), f(Integer(22)) == Integer(4), f(Integer(23)) == Integer(8)], f, n, offset=Integer(3)) >>> UB 2-regular sequence 1, 2, 2, 4, 2, 4, 6, 0, 4, 4, ...
Binary sum of digits \(S(n)\), characterized by the recurrence relations \(S(4n) = S(2n)\), \(S(4n + 1) = S(2n + 1)\), \(S(4n + 2) = S(2n + 1)\) and \(S(4n + 3) = -S(2n) + 2S(2n + 1)\):
sage: S = Seq2.from_recurrence([ ....: f(4*n) == f(2*n), ....: f(4*n + 1) == f(2*n + 1), ....: f(4*n + 2) == f(2*n + 1), ....: f(4*n + 3) == -f(2*n) + 2*f(2*n + 1), ....: f(0) == 0, f(1) == 1], f, n) sage: S 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ...
>>> from sage.all import * >>> S = Seq2.from_recurrence([ ... f(Integer(4)*n) == f(Integer(2)*n), ... f(Integer(4)*n + Integer(1)) == f(Integer(2)*n + Integer(1)), ... f(Integer(4)*n + Integer(2)) == f(Integer(2)*n + Integer(1)), ... f(Integer(4)*n + Integer(3)) == -f(Integer(2)*n) + Integer(2)*f(Integer(2)*n + Integer(1)), ... f(Integer(0)) == Integer(0), f(Integer(1)) == Integer(1)], f, n) >>> S 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ...
In order to check if this sequence is indeed the binary sum of digits, we construct it directly via its linear representation and compare it with
S
:sage: S2 = Seq2( ....: (Matrix([[1, 0], [0, 1]]), Matrix([[1, 0], [1, 1]])), ....: left=vector([0, 1]), right=vector([1, 0])) sage: (S - S2).is_trivial_zero() True
>>> from sage.all import * >>> S2 = Seq2( ... (Matrix([[Integer(1), Integer(0)], [Integer(0), Integer(1)]]), Matrix([[Integer(1), Integer(0)], [Integer(1), Integer(1)]])), ... left=vector([Integer(0), Integer(1)]), right=vector([Integer(1), Integer(0)])) >>> (S - S2).is_trivial_zero() True
Alternatively, we can also use the simpler but inhomogeneous recurrence relations \(S(2n) = S(n)\) and \(S(2n+1) = S(n) + 1\) via direct parameters:
sage: S3 = Seq2.from_recurrence(M=1, m=0, ....: coeffs={(0, 0): 1, (1, 0): 1}, ....: initial_values={0: 0, 1: 1}, ....: inhomogeneities={1: 1}) sage: S3 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... sage: (S3 - S2).is_trivial_zero() True
>>> from sage.all import * >>> S3 = Seq2.from_recurrence(M=Integer(1), m=Integer(0), ... coeffs={(Integer(0), Integer(0)): Integer(1), (Integer(1), Integer(0)): Integer(1)}, ... initial_values={Integer(0): Integer(0), Integer(1): Integer(1)}, ... inhomogeneities={Integer(1): Integer(1)}) >>> S3 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... >>> (S3 - S2).is_trivial_zero() True
Number of Non-Zero Elements in the Generalized Pascal’s Triangle (see [LRS2017]):
sage: Seq2 = RegularSequenceRing(2, QQ) sage: P = Seq2.from_recurrence([ ....: f(4*n) == 5/3*f(2*n) - 1/3*f(2*n + 1), ....: f(4*n + 1) == 4/3*f(2*n) + 1/3*f(2*n + 1), ....: f(4*n + 2) == 1/3*f(2*n) + 4/3*f(2*n + 1), ....: f(4*n + 3) == -1/3*f(2*n) + 5/3*f(2*n + 1), ....: f(0) == 1, f(1) == 2], f, n) sage: P 2-regular sequence 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, ...
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), QQ) >>> P = Seq2.from_recurrence([ ... f(Integer(4)*n) == Integer(5)/Integer(3)*f(Integer(2)*n) - Integer(1)/Integer(3)*f(Integer(2)*n + Integer(1)), ... f(Integer(4)*n + Integer(1)) == Integer(4)/Integer(3)*f(Integer(2)*n) + Integer(1)/Integer(3)*f(Integer(2)*n + Integer(1)), ... f(Integer(4)*n + Integer(2)) == Integer(1)/Integer(3)*f(Integer(2)*n) + Integer(4)/Integer(3)*f(Integer(2)*n + Integer(1)), ... f(Integer(4)*n + Integer(3)) == -Integer(1)/Integer(3)*f(Integer(2)*n) + Integer(5)/Integer(3)*f(Integer(2)*n + Integer(1)), ... f(Integer(0)) == Integer(1), f(Integer(1)) == Integer(2)], f, n) >>> P 2-regular sequence 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, ...
Finally, the same sequence can also be obtained via direct parameters without symbolic equations:
sage: Seq2.from_recurrence(M=2, m=1, ....: coeffs={(0, 0): 5/3, (0, 1): -1/3, ....: (1, 0): 4/3, (1, 1): 1/3, ....: (2, 0): 1/3, (2, 1): 4/3, ....: (3, 0): -1/3, (3, 1): 5/3}, ....: initial_values={0: 1, 1: 2}) 2-regular sequence 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, ...
>>> from sage.all import * >>> Seq2.from_recurrence(M=Integer(2), m=Integer(1), ... coeffs={(Integer(0), Integer(0)): Integer(5)/Integer(3), (Integer(0), Integer(1)): -Integer(1)/Integer(3), ... (Integer(1), Integer(0)): Integer(4)/Integer(3), (Integer(1), Integer(1)): Integer(1)/Integer(3), ... (Integer(2), Integer(0)): Integer(1)/Integer(3), (Integer(2), Integer(1)): Integer(4)/Integer(3), ... (Integer(3), Integer(0)): -Integer(1)/Integer(3), (Integer(3), Integer(1)): Integer(5)/Integer(3)}, ... initial_values={Integer(0): Integer(1), Integer(1): Integer(2)}) 2-regular sequence 1, 2, 3, 3, 4, 5, 5, 4, 5, 7, ...
- guess(f, n_verify=100, max_exponent=10, sequence=None)[source]¶
Guess a \(k\)-regular sequence whose first terms coincide with \((f(n))_{n\geq0}\).
INPUT:
f
– a function (callable) which determines the sequence. It takes nonnegative integers as an inputn_verify
– (default:100
) a positive integer. The resulting \(k\)-regular sequence coincides with \(f\) on the firstn_verify
terms.max_exponent
– (default:10
) a positive integer specifying the maximum exponent of \(k\) which is tried when guessing the sequence, i.e., relations between \(f(k^t n+r)\) are used for \(0\le t\le \mathtt{max\_exponent}\) and \(0\le r < k^j\)sequence
– (default:None
) a \(k\)-regular sequence used for bootstrapping the guessing by adding information of the linear representation ofsequence
to the guessed representation
OUTPUT: a
RegularSequence
ALGORITHM:
For the purposes of this description, the right vector valued sequence associated with a regular sequence consists of the corresponding matrix product multiplied by the right vector, but without the left vector of the regular sequence.
The algorithm maintains a right vector valued sequence consisting of the right vector valued sequence of the argument
sequence
(replaced by an empty tuple ifsequence
isNone
) plus several components of the shape \(m \mapsto f(k^t\cdot m +r)\) for suitablet
andr
.Implicitly, the algorithm also maintains a \(d \times n_\mathrm{verify}\) matrix
A
(whered
is the dimension of the right vector valued sequence) whose columns are the current right vector valued sequence evaluated at the nonnegative integers less than \(n_\mathrm{verify}\) and ensures that this matrix has full row rank.EXAMPLES:
Binary sum of digits:
sage: @cached_function ....: def s(n): ....: if n == 0: ....: return 0 ....: return s(n//2) + ZZ(is_odd(n)) sage: all(s(n) == sum(n.digits(2)) for n in srange(10)) True sage: [s(n) for n in srange(10)] [0, 1, 1, 2, 1, 2, 2, 3, 1, 2]
>>> from sage.all import * >>> @cached_function ... def s(n): ... if n == Integer(0): ... return Integer(0) ... return s(n//Integer(2)) + ZZ(is_odd(n)) >>> all(s(n) == sum(n.digits(Integer(2))) for n in srange(Integer(10))) True >>> [s(n) for n in srange(Integer(10))] [0, 1, 1, 2, 1, 2, 2, 3, 1, 2]
Let us guess a \(2\)-linear representation for \(s(n)\):
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: import logging sage: logging.getLogger().setLevel(logging.INFO) sage: S1 = Seq2.guess(s); S1 INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+1} 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... sage: S1.linear_representation() ((1, 0), Finite family {0: [1 0] [0 1], 1: [ 0 1] [-1 2]}, (0, 1))
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> import logging >>> logging.getLogger().setLevel(logging.INFO) >>> S1 = Seq2.guess(s); S1 INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+1} 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... >>> S1.linear_representation() ((1, 0), Finite family {0: [1 0] [0 1], 1: [ 0 1] [-1 2]}, (0, 1))
The
INFO
messages mean that the right vector valued sequence is the sequence \((s(n), s(2n+1))^\top\).We guess again, but this time, we use a constant sequence for bootstrapping the guessing process:
sage: C = Seq2.one_hadamard(); C 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ... sage: S2 = Seq2.guess(s, sequence=C); S2 INFO:...:including 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ... INFO:...:including f_{1*m+0} 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... sage: S2.linear_representation() ((0, 1), Finite family {0: [1 0] [0 1], 1: [1 0] [1 1]}, (1, 0)) sage: S1 == S2 True
>>> from sage.all import * >>> C = Seq2.one_hadamard(); C 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ... >>> S2 = Seq2.guess(s, sequence=C); S2 INFO:...:including 2-regular sequence 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ... INFO:...:including f_{1*m+0} 2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ... >>> S2.linear_representation() ((0, 1), Finite family {0: [1 0] [0 1], 1: [1 0] [1 1]}, (1, 0)) >>> S1 == S2 True
The sequence of all natural numbers:
sage: S = Seq2.guess(lambda n: n); S INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+1} 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... sage: S.linear_representation() ((1, 0), Finite family {0: [2 0] [2 1], 1: [ 0 1] [-2 3]}, (0, 1))
>>> from sage.all import * >>> S = Seq2.guess(lambda n: n); S INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+1} 2-regular sequence 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ... >>> S.linear_representation() ((1, 0), Finite family {0: [2 0] [2 1], 1: [ 0 1] [-2 3]}, (0, 1))
The indicator function of the even integers:
sage: S = Seq2.guess(lambda n: ZZ(is_even(n))); S INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+0} 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... sage: S.linear_representation() ((1, 0), Finite family {0: [0 1] [0 1], 1: [0 0] [0 1]}, (1, 1))
>>> from sage.all import * >>> S = Seq2.guess(lambda n: ZZ(is_even(n))); S INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+0} 2-regular sequence 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ... >>> S.linear_representation() ((1, 0), Finite family {0: [0 1] [0 1], 1: [0 0] [0 1]}, (1, 1))
The indicator function of the odd integers:
sage: S = Seq2.guess(lambda n: ZZ(is_odd(n))); S INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+1} 2-regular sequence 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, ... sage: S.linear_representation() ((1, 0), Finite family {0: [0 0] [0 1], 1: [0 1] [0 1]}, (0, 1)) sage: logging.getLogger().setLevel(logging.WARN)
>>> from sage.all import * >>> S = Seq2.guess(lambda n: ZZ(is_odd(n))); S INFO:...:including f_{1*m+0} INFO:...:including f_{2*m+1} 2-regular sequence 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, ... >>> S.linear_representation() ((1, 0), Finite family {0: [0 0] [0 1], 1: [0 1] [0 1]}, (0, 1)) >>> logging.getLogger().setLevel(logging.WARN)
The following linear representation of \(S\) is chosen badly (is degenerated, see
is_degenerated()
), as \(\mu(0)\) applied on \(\mathit{right}\) does not equal \(\mathit{right}\):sage: S = Seq2((Matrix([2]), Matrix([3])), vector([1]), vector([1]), ....: allow_degenerated_sequence=True) sage: S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... sage: S.is_degenerated() True
>>> from sage.all import * >>> S = Seq2((Matrix([Integer(2)]), Matrix([Integer(3)])), vector([Integer(1)]), vector([Integer(1)]), ... allow_degenerated_sequence=True) >>> S 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... >>> S.is_degenerated() True
However, we can
guess()
a \(2\)-regular sequence of dimension \(2\):sage: G = Seq2.guess(lambda n: S[n]) sage: G 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... sage: G.linear_representation() ((1, 0), Finite family {0: [ 0 1] [-2 3], 1: [3 0] [6 0]}, (1, 1)) sage: G == S.regenerated() True
>>> from sage.all import * >>> G = Seq2.guess(lambda n: S[n]) >>> G 2-regular sequence 1, 3, 6, 9, 12, 18, 18, 27, 24, 36, ... >>> G.linear_representation() ((1, 0), Finite family {0: [ 0 1] [-2 3], 1: [3 0] [6 0]}, (1, 1)) >>> G == S.regenerated() True
- one()[source]¶
Return the one element of this
RegularSequenceRing
, i.e. the unique neutral element for \(*\) and also the embedding of the one of the coefficient ring into thisRegularSequenceRing
.EXAMPLES:
sage: Seq2 = RegularSequenceRing(2, ZZ) sage: O = Seq2.one(); O 2-regular sequence 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, ... sage: O.linear_representation() ((1), Finite family {0: [1], 1: [0]}, (1))
>>> from sage.all import * >>> Seq2 = RegularSequenceRing(Integer(2), ZZ) >>> O = Seq2.one(); O 2-regular sequence 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, ... >>> O.linear_representation() ((1), Finite family {0: [1], 1: [0]}, (1))
- some_elements()[source]¶
Return some elements of this \(k\)-regular sequence.
See
TestSuite
for a typical use case.OUTPUT: an iterator
EXAMPLES:
sage: tuple(RegularSequenceRing(2, ZZ).some_elements()) (2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ..., 2-regular sequence 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, ..., 2-regular sequence 1, 1, 0, 1, -1, 0, 0, 1, -2, -1, ..., 2-regular sequence 2, -1, 0, 0, 0, -1, 0, 0, 0, 0, ..., 2-regular sequence 1, 1, 0, 1, 5, 0, 0, 1, -33, 5, ..., 2-regular sequence -5, 0, 0, 0, 0, 0, 0, 0, 0, 0, ..., 2-regular sequence -59, -20, 0, -20, 0, 0, 0, -20, 0, 0, ..., ... 2-regular sequence 2210, 170, 0, 0, 0, 0, 0, 0, 0, 0, ...)
>>> from sage.all import * >>> tuple(RegularSequenceRing(Integer(2), ZZ).some_elements()) (2-regular sequence 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, ..., 2-regular sequence 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, ..., 2-regular sequence 1, 1, 0, 1, -1, 0, 0, 1, -2, -1, ..., 2-regular sequence 2, -1, 0, 0, 0, -1, 0, 0, 0, 0, ..., 2-regular sequence 1, 1, 0, 1, 5, 0, 0, 1, -33, 5, ..., 2-regular sequence -5, 0, 0, 0, 0, 0, 0, 0, 0, 0, ..., 2-regular sequence -59, -20, 0, -20, 0, 0, 0, -20, 0, 0, ..., ... 2-regular sequence 2210, 170, 0, 0, 0, 0, 0, 0, 0, 0, ...)
- sage.combinat.regular_sequence.pad_right(T, length, zero=0)[source]¶
Pad
T
to the right by usingzero
to have at least the givenlength
.INPUT:
T
– tuple, list or other iterablelength
– nonnegative integerzero
– (default:0
) the elements to pad with
OUTPUT: an object of the same type as
T
EXAMPLES:
sage: from sage.combinat.regular_sequence import pad_right sage: pad_right((1, 2, 3), 10) (1, 2, 3, 0, 0, 0, 0, 0, 0, 0) sage: pad_right((1, 2, 3), 2) (1, 2, 3) sage: pad_right([(1, 2), (3, 4)], 4, (0, 0)) [(1, 2), (3, 4), (0, 0), (0, 0)]
>>> from sage.all import * >>> from sage.combinat.regular_sequence import pad_right >>> pad_right((Integer(1), Integer(2), Integer(3)), Integer(10)) (1, 2, 3, 0, 0, 0, 0, 0, 0, 0) >>> pad_right((Integer(1), Integer(2), Integer(3)), Integer(2)) (1, 2, 3) >>> pad_right([(Integer(1), Integer(2)), (Integer(3), Integer(4))], Integer(4), (Integer(0), Integer(0))) [(1, 2), (3, 4), (0, 0), (0, 0)]
- sage.combinat.regular_sequence.value(D, k)[source]¶
Return the value of the expansion with digits \(D\) in base \(k\), i.e.
\[\sum_{0\leq j < \operatorname{len}D} D[j] k^j.\]INPUT:
D
– tuple or other iterablek
– the base
OUTPUT:
An element in the common parent of the base \(k\) and of the entries of \(D\)
EXAMPLES:
sage: from sage.combinat.regular_sequence import value sage: value(42.digits(7), 7) 42
>>> from sage.all import * >>> from sage.combinat.regular_sequence import value >>> value(Integer(42).digits(Integer(7)), Integer(7)) 42